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## #1 2013-11-24 22:37:06

BenLee
Guest

### Need Logarithm Help.

Hello I have been trying this questions forever to no avail. Could anyone help me?

A. Using the laws of logarithms, simplify x-0.45 = 0.521 and evaluate for x [5 marks]

B. Find the fifth root of 600 using logarithms. [4 marks]

## #2 2013-11-24 22:45:41

bobbym

Offline

### Re: Need Logarithm Help.

Hi;

A. Using the laws of logarithms, simplify x-0.45 = 0.521 and evaluate for x [5 marks]

Why do you need logarithms to solve a linear equation?

For B, what are you allowed to use? A calculator? A log table?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #3 2013-11-24 22:48:32

Benlee
Guest

### Re: Need Logarithm Help.

Wow... Didn't know it was that simple... haha, but it is an assignment and unfortunately I need to use logarithm for it. I was thinking of putting "lg" on both sides, but not sure if that's the correct way.

## #4 2013-11-24 22:52:43

bobbym

Offline

### Re: Need Logarithm Help.

Do you have the right problem?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #5 2013-11-24 22:59:43

BenLee
Guest

### Re: Need Logarithm Help.

Apologies, knew something was not right. I typed wrongly.

A. Using the laws of logarithms, simplify x^-0.45 = 0.521 and evaluate for x [5 marks]

## #6 2013-11-24 23:03:11

bobbym

Offline

### Re: Need Logarithm Help.

x^-0.45 = 0.521

When you take the log of both sides what do you get?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #7 2013-11-24 23:08:24

BenLee
Guest

### Re: Need Logarithm Help.

lg x^-0.45 = lg 0.521

Is this right? Seems weird to me.

## #8 2013-11-24 23:14:15

bobbym

Offline

### Re: Need Logarithm Help.

That is correct and what is log(x^(-.45)) ?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #9 2013-11-24 23:18:39

BenLee
Guest

### Re: Need Logarithm Help.

I got -0.45 lgx = lg 0.521
lg x = 0.629

Is that the answer or do i need to move the lg to make x the subject? o.o

## #10 2013-11-24 23:29:25

bobbym

Offline

### Re: Need Logarithm Help.

What did you get for  lg 0.521?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #11 2013-11-24 23:32:37

BenLee
Guest

### Re: Need Logarithm Help.

I got -0.283162276 and i divided that by -0.45 to get 0.629

## #12 2013-11-24 23:39:42

bobbym

Offline

### Re: Need Logarithm Help.

That is correct. So what do you have left?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #13 2013-11-24 23:41:16

BenLee
Guest

### Re: Need Logarithm Help.

I have lg x = 0.629 left.

Should i make x the subject now or is that the answer? o.o

## #14 2013-11-24 23:42:17

bobbym

Offline

### Re: Need Logarithm Help.

What is the inverse of log(x)?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

BenLee
Guest

Is it log x^-1?

## #16 2013-11-24 23:45:47

bobbym

Offline

### Re: Need Logarithm Help.

You are using the common log?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #17 2013-11-24 23:49:04

BenLee
Guest

### Re: Need Logarithm Help.

I guess so, the other log thingy is "ln"

## #18 2013-11-24 23:52:47

bobbym

Offline

### Re: Need Logarithm Help.

When we say log(3) we mean what power must 10 be raised to, to get 3.

So what do you think now is the inverse of log? You should get raising 10 to the power of.

So taking 10^ of both sides what do you get?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.