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## #1 2013-10-20 04:19:50

ninjaman
Member
Registered: 2013-10-15
Posts: 55

### 2-x = x-2, is this correct?

hello
I have to do another partial fraction but with (2-x)^2

im not sure if its

when x = 2-, or
when x = -2

it looks like (+2-x), it doesn't look like a minus. could it be that -x is treated as -1 so it becomes,

when x = +1 so it would be (2-+1) leaving just 1.

is this right im not sure.

I also have (1+x) and im not sure what to do with that either. can I just swap them like (x+1) that doesn't seem right though. after using 6 for x I get 7 either way. 1+6 or 6+1 but this doesn't work for the 2- as the answer would be the same just one would be minus the other positive. unless im completely confused on the matter......somethings cooking, smells like brain!!!

cheers
simon:)

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## #2 2013-10-20 04:36:50

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: 2-x = x-2, is this correct?

I also have (1+x) and im not sure what to do with that either. can I just swap them like (x+1)

You can say ( x + 1 ) = ( 1 + x ). It does work for -2.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #3 2013-10-20 04:56:20

ninjaman
Member
Registered: 2013-10-15
Posts: 55

### Re: 2-x = x-2, is this correct?

im not sure how to write it, when x = 2-, is this correct

so would it be 2++1

so if I had (2-x)(1+x) and x = 2+ (instead of 2-)

it would be (2-+2) and (1++2)

is this correct, please could you point me in the right direction.

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## #4 2013-10-20 05:10:29

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: 2-x = x-2, is this correct?

im not sure how to write it, when x = 2-, is this correct

The sign goes in front like this -2. That is negative 2.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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