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**ninjaman****Member**- Registered: 2013-10-15
- Posts: 55

hello

I have to do another partial fraction but with (2-x)^2

im not sure if its

when x = 2-, or

when x = -2

it looks like (+2-x), it doesn't look like a minus. could it be that -x is treated as -1 so it becomes,

when x = +1 so it would be (2-+1) leaving just 1.

is this right im not sure.

I also have (1+x) and im not sure what to do with that either. can I just swap them like (x+1) that doesn't seem right though. after using 6 for x I get 7 either way. 1+6 or 6+1 but this doesn't work for the 2- as the answer would be the same just one would be minus the other positive. unless im completely confused on the matter......somethings cooking, smells like brain!!!

please help!!!

cheers

simon:)

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,467

I also have (1+x) and im not sure what to do with that either. can I just swap them like (x+1)

You can say ( x + 1 ) = ( 1 + x ). It does work for -2.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**ninjaman****Member**- Registered: 2013-10-15
- Posts: 55

im not sure how to write it, when x = 2-, is this correct

so would it be 2++1

so if I had (2-x)(1+x) and x = 2+ (instead of 2-)

it would be (2-+2) and (1++2)

is this correct, please could you point me in the right direction.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,467

im not sure how to write it, when x = 2-, is this correct

The sign goes in front like this -2. That is negative 2.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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