Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**AlbertMThomas****Member**- Registered: 2013-08-21
- Posts: 9

A light triangular plate OAB is in a horizontal plane. Three forces, F1=4N, F2=12N, and F3=4N, act on the plate, which is pivoted about a vertical axis through point O. Find the torque (or "moment") of force F1 about the axis through point O.

I don't understand :"Find the torque (or "moment") of force F1 about the axis through point O"

Please solve with steps

*Last edited by AlbertMThomas (2013-08-21 19:55:07)*

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,861

hi

F1 is trying to cause a rotation around O.

the moment of the force is the product of the size of the force times the perpendicular distance from O to the line of action of the force

You can use trig to get d.

Bob

Sometimes it is easier to split F1 into a horizontal component (F1cos30) and a vertical component (F1sin30) and then get the moment of each.

As the vertical component acts through O it will have zero moment.

If you do it this way you'll get the same answer so it would be worth trying both just for the practice.

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**AlbertMThomas****Member**- Registered: 2013-08-21
- Posts: 9

Thanks

Offline

Pages: **1**