Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20051117 12:24:17
Yet another integration problem...Hi all, im new here and desparately need some help, itl probably be tooe asy for you guys, but i just cant seem to find the solution, so here goes... Last edited by CloudV3 (20051117 12:56:40) #2 20051117 18:26:51
Re: Yet another integration problem...v = 5t²+2t Character is who you are when no one is looking. #3 20051125 02:50:16
Re: Yet another integration problem...Actually the constant C is not necessarily 0 in this case. True, velocity is 0 at t=0, but the C of integration of the velocity function represents the inital position of the particle at t=0. This was not specifically stated in the question. 