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**purpeil****Guest**

for any complex number z prove that - I z I < or equal to Re (z) < or equal to I z I

**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

I'm assuming u mean abs(z) by IzI in which case z=a+bi.Re(z)=a and abs(z)=square root of a^2+b^2

now,a^2<a^2+b^2 [equal in case of b=0] taking positive square root |a|<abs(z),by the inequality law of absoloute value,-abs(z)<a<abs(z)

*Last edited by {7/3} (2013-06-28 05:10:21)*

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