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**angelpumpingas****Member**- Registered: 2005-11-14
- Posts: 9

I'm really confused on problems with square roots... Can someone please explain to me how to do this problem? It would be greatly appreciated. ^_^ I'm sure it's something simple, but I'm so confused.

√1+sinθ/1-sinθ = 1+sinθ/|cosθ|

<3Angel~

Swimming through sick lullabies, Choking on your alibis...

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**Flowers4Carlos****Member**- Registered: 2005-08-25
- Posts: 106

hi yaz angel!!

what does "<3" in your signature mean??? i see that expression being used a lot lately.

(1+sinθ)^(1/2) (1+sinθ)

------------------ = ----------- the left side is easier to work with

(1-sinθ)^(1/2) |cosθ|

(1+sinθ)^(1/2)

------------------ multiply everything by the "conjugate" of the denominator

(1-sinθ)^(1/2)

(1+sinθ)^(1/2)*(1+sinθ)^(1/2) (1+sinθ)^(2/2) 1+sinθ

------------------------------------ = ------------------------------ = ------------------

(1-sinθ)^(1/2)*(1+sinθ)^(1/2) [(1-sinθ)(1+sinθ)]^(1/2) (1-sin²θ)^(1/2)

1+sinθ

------------------ remember the identity cos²θ = 1-sin²θ

(1-sin²θ)^(1/2)

1+sinθ 1+sinθ

------------------ = ---------------- since √a ≥ 0, then √cos²θ > 0 ⇒ |cosθ|

(cos²θ)^(1/2) (cosθ)^(2/2)

1+sinθ 1+sinθ

--------- = ---------

√cos²θ |cosθ|

*Last edited by Flowers4Carlos (2005-11-14 16:18:57)*

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**angelpumpingas****Member**- Registered: 2005-11-14
- Posts: 9

Omg... Thank you so much for your help. ^_^ It is greatly appreciated....

And <3 is just a symbol for a heart... I use it more than I should, really... But oh well.

Thanks again!!

<3Angel~

Swimming through sick lullabies, Choking on your alibis...

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**Flowers4Carlos****Member**- Registered: 2005-08-25
- Posts: 106

ahhh... a heart! yes i recognize those!! they are the ones that are always fluttering about chris evans.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,654

Gee, good work there Flowers.

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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