Hi hopefully you guys can help me with this problem sum.
there are 45 coins in the piggy bank.
total amount is $21.90
there are 7 $1 coins in the piggy bank.
how many $0.50 and $0.20 coins are there in the piggy bank?
Welcome to the forum.
I've made two equations from this information and tried to solve the problem. But the number of $0.50 coins has come out as a fraction so either I've made a silly error or the information has a typo. Have a look and see if you can sort it out; the method should work.
First some letters for the number of coins. I'm from the UK so I couldn't remember what you call those coins so for $0.50 I'm using H and for $0.20 I'm using F.
First equation based on number of coins
Second based on value of coins
Multiply the first by 2 and subtract the result from the second
Now if 73 was in the 3x table that would give H and F would quickly follow. But you cannot have H not a whole number so I'm stuck.
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
There are no integer solutions to that problem.
I think the problem is a typo. Now total amount is $21.80 has a solution.
In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.