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#1 2013-05-06 03:02:09

ShivamS
Member
Registered: 2011-02-07
Posts: 3,610

Some contour integration

99% chance I am wrong...
Also, do not know Latex.
I =  ∫  infinity on top, 0 on bottom     (x^alpha)/(1+ √2x +x^2)dx

I am getting I = (√2pi)sin(alpha pi/4)  /  sin(alpha pi)

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#2 2013-05-06 04:20:52

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,606

Re: Some contour integration

M is getting

for -1<alpha<1.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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#3 2013-05-08 00:47:16

ShivamS
Member
Registered: 2011-02-07
Posts: 3,610

Re: Some contour integration

How do you get that? And M?

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#4 2013-05-08 05:08:49

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,606

Re: Some contour integration

Mathematica.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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