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How many ordered pairs of non-negative integers (a,b) are there such that √a+√b=√432 ?

Since, √432 = 12√3, therefore the pairs are 0 + (12√3)^2, (√3)^2 + (11√3)^2, (2√3)^2 + (9√3)^2, and so on. So a total of 12 ordered pairs.

Why is this wrong?

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 108,586

I am getting 6 with a>b.

13 with order counting.

I counted them up.

{0,432}

{3,363}

{12,300}

{27,243}

{48,192}

{75,147}

{108,108}

{147,75}

{192,48}

{243,27}

{300,12}

{363,3}

{432,0}

Oh, sorry it already got answered.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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Oh yeah! I missed the question totally

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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