Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #2 20130410 18:15:51
Re: Nehushtan’s challenge problems#1 is not true. Try x=y=z=2. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #4 20130416 00:06:41
Re: Nehushtan’s challenge problemsHi, Adding those two would yield "Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense"  Buddha? "Data! Data! Data!" he cried impatiently. "I can't make bricks without clay." #6 20130416 06:28:33
Re: Nehushtan’s challenge problemsx <= y <= z implies Y >= x #7 20130416 08:00:36
Re: Nehushtan’s challenge problemsThat only works when all three numbers are positive. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #8 20130416 09:54:55
Re: Nehushtan’s challenge problemsCase 1: (same proof as my original answer) 