Discussion about math, puzzles, games and fun. Useful symbols: χ Χ ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -Ή ² ³ °
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You are not logged in. #1 2013-01-30 23:09:39
Topsy-turvy continuityBackground. As you would now, the continuity12 of a function f at x0, a point in the domain of f, is defined using a condition in f's codomain first ("given ε > 0
∣f(x) - f(x0)∣ < ε") and then proceeds with a condition in f's domain ("
then there exists a δ > 0
∣x - x0∣ < δ"). I majored in Physics in 1976. Also, I studied mathematics and computer science. I work as a computer programmer. I am from Norway. #2 2013-01-31 00:35:51
Re: Topsy-turvy continuityhi Ivar, You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #3 2013-01-31 01:18:41
Re: Topsy-turvy continuityWhere did you get the definition in the first paragraph from, because I see a different one on Wikipedia... The limit operator is just an excuse for doing something you know you can't. It's the subject that nobody knows anything about that we can all talk about! ― Richard Feynman A secret's worth depends on the people from whom it must be kept. ― Carlos Ruiz Zafσn #4 2013-01-31 21:07:24
Re: Topsy-turvy continuityNo, Bob, I haven't. I suppose you are thinking about whether continuity implies topsy-turvy continuity. I don't think this is true so a counter-proof would be called for. I believe the problem is connected to points in f's domain where f has an infinite derivative. Let's have a closer look. Last edited by Ivar Sand (2013-02-04 22:24:02) I majored in Physics in 1976. Also, I studied mathematics and computer science. I work as a computer programmer. I am from Norway. #5 2013-01-31 21:44:14
Re: Topsy-turvy continuityWell, anonimnystefy, let's see. We go to the Wikipedia page named "Continuous function", the paragraph "Weierstrass definition (epsilon-delta) of continuous functions" and the sentence "For any number ε > 0,
". This sentence expresses something like: given an ε > 0, a δ > 0 exists
, where ε is part of a condition in the codomain and δ is part of a condition in the domain. Topsy-turvy continuity, on the other hand, looks like: given a δ > 0, a k > 0 exists
, where δ is part of a condition in the domain and k is part of a condition in the codomain. I majored in Physics in 1976. Also, I studied mathematics and computer science. I work as a computer programmer. I am from Norway. #6 2013-01-31 22:33:35
Re: Topsy-turvy continuityhi Ivar Sand You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #7 2013-02-01 20:16:55
Re: Topsy-turvy continuityI see, Bob. I agree that f is not differentiable at x0. I'm sorry about that. I propose to replace in post #4: Last edited by Ivar Sand (2013-02-01 20:22:16) I majored in Physics in 1976. Also, I studied mathematics and computer science. I work as a computer programmer. I am from Norway. #8 2013-02-04 22:26:59
Re: Topsy-turvy continuityNow I have updated post #4. I have removed the word differentiable and also made other changes in order to make the mathematics more precise. I majored in Physics in 1976. Also, I studied mathematics and computer science. I work as a computer programmer. I am from Norway. |