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## #1 2013-01-11 22:06:44

Fistfiz
Member
Registered: 2012-07-20
Posts: 33

### Wronksian determinant in 2nd order linear DE

Hi guys,
I'm studying some demonstrations about 2nd order differential equations of the form:
y''+2by'+ay=f(t)
where a,b are constants.
Suppose that u,v are linearly independent solutions. Now, in several demonstrations, it's needed that the Wronksian determinant of u,v it's different from zero.
I see from Abel's identity (http://en.wikipedia.org/wiki/Abel's_identity) that if this is true for some t0 value, then it's true for all t. Provided this, can I always say that the Wronksian of u,v is always non-zero??

30+2=28 (Mom's identity)

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## #2 2013-01-12 00:35:41

scientia
Member
Registered: 2009-11-13
Posts: 224

### Re: Wronksian determinant in 2nd order linear DE

Yes, if you can show that
for some
then
for all
.

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## #3 2013-01-12 02:06:52

Fistfiz
Member
Registered: 2012-07-20
Posts: 33

### Re: Wronksian determinant in 2nd order linear DE

Of course but what i meant was: can I avoid to include W(t0)!=0 for some t0 in my hypotesis? In other words, if I have two linearly independent solutions u and v, can I automatically say W(u,v)!=0 for all t?

30+2=28 (Mom's identity)

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## #4 2013-01-12 02:39:21

scientia
Member
Registered: 2009-11-13
Posts: 224

### Re: Wronksian determinant in 2nd order linear DE

I see. Well, if
are differentiable, then linear independence implies
for all
. If they are not both differentiable, then it is possible that they are linearly independent yet
. See http://en.wikipedia.org/wiki/Wronskian# … dependence for an example.

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## #5 2013-01-13 02:06:45

Fistfiz
Member
Registered: 2012-07-20
Posts: 33

### Re: Wronksian determinant in 2nd order linear DE

Thank you, this remark:
"Peano (1889) observed that if the functions are analytic, then the vanishing of the Wronskian in an interval implies that they are linearly dependent."
opened my eyes

30+2=28 (Mom's identity)

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