You are not logged in.
#1 2013-01-08 03:54:22
- jasonbosche
- Novice
Offline
Tough Math probability question
Should someone enter into a competition where he has a 1 in 1000 chance of winning, then as a winner gets entered into a second competition where he has a 1 in 1000 chance of winning what would the probability of him winning the second competition?
Is it as simple as 1000 * 1000? Or is it 2 in 2000?
I am lost please help!
#2 2013-01-08 03:58:50
- bobbym
- Administrator
Offline
Re: Tough Math probability question
Hi jasonbosche;
Welcome to the forum.
Should someone enter into a competition where he has a 1 in 1000 chance of winning.
That question can only be answered in terms of expectation.
You are asking the chance of winning 2 tournaments both at 1 / 1000?
It is simply
( 1 / 1000 ) (1 / 1000 ) = 1 / 1000000
His chance of winning the second tournament is just 1 / 1000.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#3 2013-01-08 04:11:32
- jasonbosche
- Novice
Offline
Re: Tough Math probability question
Ok great thanks.
So his chance is 1 in a million to win two in a row, so if we had to add this onto the question.
The chances he has of winning 3 competitions in a row where each of them he has a 1 in 1000 chance of winning.
This would be 1000* 1000*1000 = 1 a in a billion chance?
arent there some other factors that make his chances higher, i mean if winning the lotto is a one in a 175 million chance i would think winning three in row where theer are 1 in 1000 chances would give him better chances... If you know what i mean..
#4 2013-01-08 04:16:15
- bobbym
- Administrator
Offline
Re: Tough Math probability question
Hi;
arent there some other factors that make his chances higher,
It depends on how sure you are of the 1 chance in a 1000. If that is an estimated probability ( subjective probability ) then there is some room for error. If that is an exact probability ( objective probability ) like the odds of getting a six when you throw a die then
( 1 / 1000 ) ( 1 / 1000 ) ( 1 / 1000 ) = 1/1000000000
is the chance of winning all three tournaments.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#5 2013-01-08 04:26:26
- jasonbosche
- Novice
Offline
Re: Tough Math probability question
I would say its subjective probability because there is some skill in the game.
Does that change anything?
Lets say the game is 20% skill
Last edited by jasonbosche (2013-01-08 04:27:00)
#6 2013-01-08 04:29:11
- bobbym
- Administrator
Offline
Re: Tough Math probability question
Sure does change things, the question is much more complicated now. What do you mean by 20% skill, please be exact.
Do you feel that player has a 20% chance of victory?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#7 2013-01-08 04:56:32
- jasonbosche
- Novice
Offline
Re: Tough Math probability question
Lets say the game is mostly chance but there is a certain aspect of skill, like 20% of the game would be skill and 80% absolute game of chance.
like blackjack for example, some players do the wrong things and then the bank has a bigger chance of winning, normally their advantage is 20% but with a bad player its 35% advantage.
If that makes sense... There is a certain aspect of skill but not a lot only 20%
#8 2013-01-08 05:03:06
- bobbym
- Administrator
Offline
Re: Tough Math probability question
hI jasonbosche;
bigger chance of winning, normally their advantage is 20% but with a bad player its 35% advantage.
The house edge against a good player in blackjack is very small, less than 1%. Against a good card counter they have a negative percentage depending on the game and the bet spread. Who knows how much of a disadvatage a bad player is at.
Basically the question you have to ask is, is the player playing with a positive expectation or a negative one? That is the only stat that counts.
For instance, the house has about a 2% advantage on the average player on a blackjack table. That means for every dollar bet the house wins 51 cents and player win 49 cents, regardless of who wins any particular bet. This expectation stays the same. The player loses 2 cents on every dollar bet.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.