You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Frublox****Member**- Registered: 2012-12-19
- Posts: 1

Got this problem on a test:

____

12 + √2x-1 = 4

Okay, so then I subtract 12 from both sides:

____

√2x-1 = -8

2x - 1 = 64 I then square both sides...

2x = 65 Add 1 to each side

x = 65/2 Divide both sides by two.

However, that answer doesn't work. Are there simply no solutions, then?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,394

Hi Frublox;

That is correct, there are no solutions. Not every equation is a true statement. You always check the validity of your answer by plugging into the original equation.

Please go here:

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

hi Frublox

That answer is the solution to

-12 + √(2x-1) = -4

When you square you cannot help but introduce 'solutions' to this alternative equation as well so you were right to check the value you had.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,809

Even when you got √2x-1 = -8 you could've said that there are no solutions, because a square root of a positive number is always positive...

Here lies the reader who will never open this book. He is forever dead.

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 81,394

Hi;

Yes, it always takes the principal value.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

Pages: **1**