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You are not logged in. #1 20121121 05:34:00
eigen pair by power methodCan anyone tell me how to solve a problem using c program by "eigen pair by power method"? #2 20121121 09:41:19
Re: eigen pair by power methodHi princess snowwhite; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20121121 18:53:40
Re: eigen pair by power methodMabe she means eigenvalue and the corresponding eigenvector? : The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #4 20121121 20:52:49
Re: eigen pair by power methodHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20121122 00:37:18
Re: eigen pair by power methodWell, from the eigenvalue you can get the corresponding eigenvector... The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #6 20121122 00:41:55
Re: eigen pair by power methodWe won't have the eigenvalue, the power method gets through iteration an approximation to either the largest or the smallest eigenvalue. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20121122 03:46:22
Re: eigen pair by power methodI don't know what is this eigen pair, THAT'S WHY i am asking you #8 20121122 04:12:07
Re: eigen pair by power methodWhere'd you get the term "eigen pair" from, then? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #9 20121122 09:37:22
Re: eigen pair by power methodHi princess snowwhite;
It appears that Mr anonimnystefy is correct, every eigenvector is associated with an eigenvalue. These are called an eigenpair. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #10 20121124 03:16:56
Re: eigen pair by power methodI needed the definition and example also #11 20121124 04:48:01
Re: eigen pair by power methodOkay, I have a nice example please hold on while I post it. We choose the initial vector with a guess of We begin to iterate using x0 and A to generate x1. Now for the purposes of keeping the elements of xn small we will divide x1 by the bottom entry in this case a 5. This was an arbitrary choice and in a real calculation we would use a better system. Now we continue to iterate. We divide x2 by the bottom element in this case 5.8 Continuing the above steps we get: It really does look like the dominant eigenvector is approaching From that eigenvector we get the dominant eigenvalue by applying this formula: where x is the dominant eigenvector and A is original matrix ( above ). That is the dominant eigenvalue. We are done. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 