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## #1 2005-10-16 06:13:41

Jaswahhihi
Member

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### Differentiation

How do you differentiate:

1 / ln x ????????????????????????????????????????????

98% of the teenage population does or has tried smoking pot. If you're one of the 2% who hasn't, copy & paste this into your signature.

## #2 2005-10-16 06:40:02

mathsyperson
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### Re: Differentiation

The quotient rule says that (u/v)' = (vu' - uv')/v², where u' and v' are the differentials of u and v with respect to x.

Taking u = 1 and v = ln x means that u' = 0 and v' = 1/x, so (u/v)' would be -1/x(ln x)².
There may be a simpler way of doing that that gives a simpler answer, but I'm sleepy so I can't see one.

Why did the vector cross the road?
It wanted to be normal.

## #3 2005-11-08 21:41:07

Ash
Guest

### Re: Differentiation

simpler way is probably using the chain rule. Take up logex to be (logex)^-1, then simply differentiate as normal:

-1(logex)^-2 x (1/x)

= -1/(x(logex)^2)

Sorry if my terminology isn't clear- im in australia and the syllabus is different here (just had my finals and im depressed over a poor effort in my most important exam...trying to find some solace by going over everything and brushing up my math skills...just can't believe how much effort i put in to make so many silly mistakes on the day...)