bobbym wrote:

A question to you, in the last month or so you have posted this message to about 75
forums. Those forums are mostly about philosophy and a smattering of other subjects. But no maths forums
except this one. Why?



Welcome to the forum.

who wants me to discuss and learn new things in mathematics is welcome who wants me to listen to his will
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Presupposition-natural long merge points in the direction of the first natural along AB
Process:
P1-AB..CD..ABC(AC)
to read- natural along AB to point B, is connected to the natural long CD to point C, shall be
P2-ABC(AC)..DE..ABCD(AD)
read- along the ABC(AC) to point C , connecting with the natural long DE to point D is done
renaming of points , we get along ABCD(AD)
P3-ABCD(AD)..EF..ABCDE(AE)
...
--image--

[S3]-along (natural basis)
Definition[along]-the first and last point and the distance between points
CM-[S3]-does not know
_________________________________________________________________________________
Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),...,
(0,1,2,3,4,5,6,7,8,9 ),...
Process:
P1-N (0) = {0,00,000,0000,...}
P2-N (0,1) = {0,1,10,11,100,...}
...
P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
...
--image--
[S4]-number along
[S5]-set of natural numbers N
We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...}
Definition[number along]- a starting point (0), the last point at infinity
[number N]-The number 0 is the point 0
-Other numbers are longer, the first item is 0, the last point is the point of the name (number)
CM-[S4].does not know , [S5]-axiom
________________________________________________
Presupposition-Numbers have their points
Process:
P1 0 = ( .0)
P2 1={(.0),(.1)}
P3 2={(.0),(.1),(.2)}
P4 3={(.0),(.1),(.2),(.3)}
P5 4={(.0),(.1),(.2),(.3),(.4)}
...
--image--
[S6]-number points
CM-[S6]does not know

Uploaded Images

Presupposition-number ranges for number along
Process:
P1-image
P2-image
P3-image
--image--
[S9]-mobility of number
CM-[S9]-does not know
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Presupposition-Number (a) and mobile number (b ) but have no contact with the item
Process:
P1 ¤3(0)2¤
P2 ¤3(1)2¤
P3 ¤3(2)2¤
...
--image--
Next - gap number and mobile number have no contact , except to point
...
[S10]-gap number GN={¤a(b)c¤,...,¤g(f)...(d)e¤}
[S11]-gap along
Definition[gap along] a>0-¤0(0)0¤-point
-¤0(a)0¤-two point ,separated by a gap
-¤a(0)0¤,¤0(0)a¤,¤a(0)a¤-along , two points
-¤a(a)a¤-two along , 4 points
...
CM-[S11],[S12] -does no know
________________
Presupposition-Number (a) and mobile number (b ) of a contat ,merge
Proces:
P1 3+(.0/.0)2=3
P2 3+(.1/.0)2=3
P3 3+(.2/.0)2=4 - image
P4 3+(.3/.0)2=5
form (.a/0) and (s.a/0) we’ll continue this write (.a) and (s.a)
--image--
P1 3+(.0)2=3
P2 3+(.1)2=3
P3 3+(.2)2=4
P4 3+(.3)2=5
General form
a+(.0)b=c
a+(.1)b=c
...
a+(.d)b=c
[S12]-addition
CM-only form a+(s.0/.0)b=c , others do not know , axiom

Uploaded Images

Presupposition-Two ( more ) srcko (pendand srcko) are combined into one unit
Process:
P₁ 10₆ and 11₈ , 10₆11₈
P₂ 10₅65 and 70₃ ,10₅65_70₃
P₃ 30₃60 and 45₂77_78 ,30₃60_45₂77_78
...
General form -a_bc_d , a_bc_d_e ,a_bc_d_ef_g ,...
[S₁₆]-two ( more) srcko
CM-[S₁₆]-does no know
_________________-
Presupposition-Two ( more ) srcko have the first ( last) common number
Process:
P₁ 10₅30 and 3₃30 , 10₅3₃(_30)
P2 4₄44 and 44₁₀94 and 44₂56 , 4₄(_44_)₁₀94₂56
...
General form -a_bc_d(_e) , a_b(_c_)_de_fg , ...
[S₁₇]-two ( more)  first-last srcko
CM-[S₁₇]-does no know
______________________________________________________
Presupposition-In the expression a+(.b)c=d , d+(s.0)1₁ or d+(s.0)number (more) from 1₁
Process:
P₁ 3+(.s.0)5=8+(s.0)1₁ , 3+(s.0)5<9₁
P₂ 5+(.0)5=5+(s.0)2₂4 , 5+(.0)5<7₂9
...
General form - a+(.b)c=d+(s.0)1₁ ,a+(s.b)c<e₁
a+(.b)c=d+(s.0)e , a+(.b)c<f
a+(.b)c=d+(s.0)e_fg , a+(.b)c<h_ij ...
[S₁₈]-left inequality
CM-[S₁₈]-know
_______________________________________
2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
srcko
5₅50={5,10,15,20,25,30,35,40,45,50}
38₃50={38,41,44,47,50}
50₁₀90={50,60,70,80,90}
50₇92={50,57,64,71,78,85,92}
two(more) first-last srcko
5₅38₃(_50_)₁₀90₇92
remains part of the function, when we come to it

Presupposition-Gap number ( value z) is a variable (same value) with the gaps that is constant 
Process:
P1  ¤5(2)0¤,¤4(2)1¤,3(2)2¤,¤2(2)3¤,¤1(2)4¤,¤0(2)5¤  --5¤¤(2)

P2 ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤     
     ¤2(2)0¤,¤1(2)1¤.¤0(2)2¤                   
     ¤1(2)0¤,¤0(2)1¤                                 
     ¤0(2)0¤  --0₁3¤¤(2)

   
     ¤2(2)0¤,¤1(2)1¤,¤0(2)2¤
     ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤
                       ...
      2₁¤¤(2)

[S22]-variability of z number
CM-[S22]-does no know
_______________
Presupposition-Translation of gap number in the variability z ( with constant gap ) can addition
(s.0)
Process:
P1 ¤3(2)3¤+(.z)¤4(2)4=6¤¤(2)+(.z)8¤¤(2)=14¤¤(2)
P2 ¤1(6)1(9)1¤+(.z)¤3(6)2(9)1¤=3¤¤(6)(9)+(.z)6¤¤(6)(9 )=9¤¤(6)(9)
...
General form ¤a(b)c¤+(.z)¤d(b)e¤=f¤¤(b )+(.z)g¤¤(b )=h¤¤(b ) ...
[S23]-z addition
CM-[S23]-does no know
__________________________________________
Presupposition-Translation of gap number in the variability z ( with constant gap ) can subtraction
(s.0/s.0)
Process:
P1 ¤3(2)3¤-(.z)¤1(2)1=6¤¤(2)-(.z)2¤¤(2)=4¤¤(2)
P2 ¤3(6)2(9)1¤-(.z)¤1(6)1(9)1¤=6¤¤(6)(9)-(.z)3¤¤(6)(9)=3¤¤(6)(9)
...
General form ¤a(b)c¤-(.z)¤d(b)e¤=f¤¤(b )-(.z)g¤¤(b )=h¤¤(b ) ...
[S24]-z subtraction
CM-[S24]-does no know

Presupposition-Two ( more) addition the same number can be written in shorted form
Process:
P1 a+(s.c)a=a×(s.c)2 , a×(s.c)b
P2 a+(s.c)a+(s.c)a=a×(s.c)3 , a×(s.c)b
P3 a+(s.c)a+(s.c)a+(s.c)a=a×(s.c)4 , a×(s.c)b
...
[S28]-multiplication
CM-[S28]-know , axiom
_____
Presupposition-In terms a×(s.c)b , b can be number 0 (1)
Process:
P1 a×(s.c)0
P2 a×(s.c)1
[S28a]-multiplication-amendment
_____________
Presupposition-In terms a×(s.c)b , multiplication
Process:
P1 4×(s.0)4=16
P2 4×(s.1)4=13 image
P3 4×(s.2)4=10
P4 4×(s.3)4=7
P5 4×(s.4)4=4

--image--
P1 ¤1(2)1¤×(s.0)4=¤1(2)2(2)2(2)2(2)1¤
P2 ¤1(2)1¤×(s.1)4=¤1(2)1(2)1(2)1(2)1¤ image
P3 ¤1(2)1¤×(s.2)4=¤1(1)6(1)1¤
P4 ¤1(2)1¤×(s.3)4=7
P5 ¤1(2)1¤×(s.4)4=¤1(2)1¤
--image--
General form
a×(s.0)b=c
a×(s.1)b=c
...
a×(c.d)b=c

[S28b]-multiplication
CM-[S28b]-know a×(s.0)b other do not know , forms withuut any gaps numbers not known

___________________________________________
Presupposition-The numbers are multiplication , where a contact is deleted
Process:
P1 4 × (s.0)4=¤4(0)4(0)4(0)4¤
P2 4 × (s.1)4=¤3(1)2(1)2(1)3¤ image
P3 4 × (s.2)4=¤2(6)2¤
P4 4 × (s.3)4=¤1(5)1¤
P5 4 × (s.4)4=0
--image--
General form
a × (s.0)b=c
a × (s.1)b=c
...
a × (c.d)b=c

[S29]-multiplication subtraction
CM-[S29]-does no know
×You will see a sign in the PDF

Uploaded Images

Presupposition-Srki and  gap srki merger (multiplication )
Process:
P1 ¤1(7)1¤=¤1(1)1(1)1(1)1¤×(s.5¤|ß3)6=¤1(1)1(1)1(1)1¤
     ¤1(1)1(1)1¤=¤1(1)1(1)1(1)¤×(s.5¤|ß4)6=0
P2 4=¤1(1)1(1)1(1)1¤×(s.6¤|ß3)6=2 image
P3  ¤1(1)1(1)1(1)1¤=¤1(1)1(1)1(1)1¤×(s.7¤|ß6)6=¤1(1)1(1)1¤
   [attachment=2682:a20.png]
General form
w=a#(s.1¤|ß3)b=c
w=a#(s.2¤|ßd)b=c
...
w=a#(s.e¤|ßf)b=c , #- calculation operations (×,...)

[S33]-two srki
CM-[S33]-does no know
[size="4"]Note - this is a two-way calculation, and therefore has two equals signs left(srki) right(gap srki)[/size]
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Presupposition-Subtraction form a-(s.0/s.0)b=0,a-(s.0/s.0)b-(s.0/s.0)b=0 , ...,a-(s.0/s.0)b-
...-(s.0/s.0)b=0 can be written differently counting the subtraction
Process:
P1 12-(..0)4=12    (..c) -counting the subtraction
    12-(..1)4=8
    12-(..2)4=4
    12-(..3)4=0
    12:4=3
General form
a-(..0)b=a
a-(..1)b=c
...
a-(..d)b=0
a:b=d

[S34]-counting the subtraction
[S35]-divide
CM-[S34]-does no know ,[S35]-know, axiom
_____________________________
Presupposition-Subtraction form a-(s.0/s.0)b=0,a-(s.0/s.0)b-(s.0/s.0)b=0 , ...,a-(s.0/s.0)b-
...-(s.0/s.0)b=0, number b can replaced b= ((s.0/s.0)c-(s./s.0)d) , b= ((s.0/s.0)c-(s.0/s.0)d-
(s./s.0)e),...,b= ((s.0/s.0)...(s.0/s.0)w) ,  can be written differently counting the subtraction
Process:
P1 12-(..0)1[SUB]1[/SUB]2=12
12-(..1)1[SUB]1[/SUB]2=11
12-(..2)1[SUB]1[/SUB]2=9
12-(..3)1[SUB]1[/SUB]2=8
12-(..4)1[SUB]1[/SUB]2=6
12-(..5)1[SUB]1[/SUB]2=5
12-(..6)1[SUB]1[/SUB]2=3
12-(..7)1[SUB]1[/SUB]2=2
12-(..8)1[SUB]1[/SUB]2=0
12:1[SUB]1[/SUB]2=8
General form
a-(..0)b[SUB]e[/SUB]f=a
a-(..1)b[SUB]e[/SUB]f=c
...
a-(..d)b[SUB]e[/SUB]f=0
a:b[SUB]e[/SUB]f=d  ...
[S36]-inequality divide
CM-[S36]-does no know

Uploaded Images

bobbym wrote:

Hi;

Can you pause and explain your ideas before moving on? If you are just intending to publish your book then vixra is a much better place to do that.

what I've realized that the whole thing in math geometry, and that everything is a ratio of two (more) geometrical object in a line, plane, n-volume, I am totally rejected the historical legacy that has a current math, I started from the first geometry object (along natural) and the concept of point and a basic rule to connect the two (more) along the natural area this is the first axiom and it does not prove,each new object (concept, calculation, ...) occurs along the natural object or arising out along natural ...
If something is unclear ask

because I do not get it, here's the work of the occurrence arranged by the sheer number of mathematical notation, mathematical journals refused to publish it, see if it's worth.
https://docs.google.com/file/d/0BzkWG0xdRpPYVTZxVThoUkJlRWs/edit

anonimnystefy wrote:

Hello msbiljanica

Should it be that you are from the Balkan area?

I am from Serbia - South Eastern Europe

PDF - Mathematics - a new base
https://skydrive.live.com/?cid=48f41121 … CF17%21105