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#1 2012-01-30 15:29:37
- NumOne
- Member
- Registered: 2012-01-16
- Posts: 9
How can I get this equation?
Hi
I have the following equation:
2a/n (1/2n^2 log n - 1/8 n^2) + Θ(n)
What are the steps that I can do to let the previous equation be the following:
a n log n - (an/4 - Θ(n))
Thanks
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#2 2012-01-31 03:03:11
- NumOne
- Member
- Registered: 2012-01-16
- Posts: 9
Re: How can I get this equation?
for clarifying the question
2a/n (1/2n^2 log n - 1/8 n^2) + Θ(n)
= ???
= ???
= ???
= ???
= a n log n - (an/4 - Θ(n))
What are the steps between both of them ?
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#3 2012-01-31 06:50:30
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: How can I get this equation?
Hi NumOne;
Welcome to the forum.
Is this what you have?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#4 2012-01-31 11:39:26
- NumOne
- Member
- Registered: 2012-01-16
- Posts: 9
Re: How can I get this equation?
No, it is :
(2a/n)(1/2 ......)
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#5 2012-01-31 14:45:10
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: How can I get this equation?
Hi;
So this is the correct question.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#6 2012-01-31 15:25:32
- TheDude
- Member
- Registered: 2007-10-23
- Posts: 361
Re: How can I get this equation?
I think he means this expression:
At least it ends up working out to the expression he's looking for:
Last edited by TheDude (2012-01-31 15:30:06)
Wrap it in bacon
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