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## #1 2005-10-13 19:02:01

anyarules
Member
Registered: 2005-07-24
Posts: 29

----------------------------------------------------------------------------------------------------------------You are given the following numbers: 11,40,4,22,0,6,10,31. You are allowed to choose any four but the sum of those four numbers must be 62. You may choose the same number any muber of times. How many different ways are there?
----------------------------------------------------------------------------------------------------------------

<^>ChallengeGirl

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## #2 2005-10-14 04:21:18

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

I get 5:

40, 22, 0, 0
40, 11, 11, 0
40, 10, 6, 6
31, 31, 0, 0
31, 11, 10, 10

But knowing my luck, I've probably missed one.

Why did the vector cross the road?
It wanted to be normal.

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## #3 2005-10-18 11:57:10

anyarules
Member
Registered: 2005-07-24
Posts: 29