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**anyarules****Member**- Registered: 2005-07-24
- Posts: 29

Please help me on this weird question. i need answers URGENTLY!!

----------------------------------------------------------------------------------------------------------------You are given the following numbers: 11,40,4,22,0,6,10,31. You are allowed to choose any four but the sum of those four numbers must be 62. You may choose the same number any muber of times. How many different ways are there?

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Please paste the answer and help a poor little girl.

<^>ChallengeGirl

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

I get 5:

40, 22, 0, 0

40, 11, 11, 0

40, 10, 6, 6

31, 31, 0, 0

31, 11, 10, 10

But knowing my luck, I've probably missed one.

Why did the vector cross the road?

It wanted to be normal.

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**anyarules****Member**- Registered: 2005-07-24
- Posts: 29

Thanx!!

<^>ChallengeGirl

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