Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Sten****Member**- Registered: 2005-09-17
- Posts: 1

I've always been terrible at working backwards from a formula.

units = 300 * (growingNumber^1.1)

The above formula determines how many units a certain item requires to complete. Each additional item increases in unit consumption to complete. My task is to determine a formula that will return the total number of items that can be built, given a certain number of units.

ie.

The above formula produces:

Item# Units

1 300

2 643

3 1,005

4 1,378

5 1,762

6 2,153

7 2,551

8 2,955

9 3,363

10 3,777

If a person has 5008 units, he can then produce 5 total Items (300+643+1005+1378+1762 = 5008).

How can I create a formula to determine that 5 total items can be produced with 5008 units, without actually calculating up every unit cost per item?

Any help would be greatly appreciated.

Regards,

Sten

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,685

Hmmm ... without the power of 1.1 it is fairly easy to calculate the "cumulative sum" - it is the average times the count.

For example, the cumulative sum of 1,2,3,4,5 is the average value (3) times the count (5) = 3x5 = 15, and the average of a series of numbers can be worked out by just averaging the first and last (ie (1+5)/2 = 3)

But the " ^1.1 " makes it a geometric series, not linear ...

So I think we are looking at "Power Sums", a slightly tricky area of mathematics that I don't have enough knowledge of.

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

Pages: **1**