Also, 23 is the sum of 3 consecutive primes.
If gcd(n,b)>1, there does not exist any sequence of n consecutive primes such that the last digit(s) in base b is n. Does such a sequence always exist when gcd(n,b)=1?
2011 is also the sum of three consecutive primes: 661, 673, and 677.
Furthermore, 2011= 39^2 + 17^2 + 7^2.
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