Math Is Fun Forum
Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 2010-10-17 01:49:46
- G_Einstein
- Member
- Registered: 2008-08-30
- Posts: 124
Double integral ....
if D is bounded by y=px^3,y=qx^3,y^2=ax,y^2=bx,where o<p<q and 0<a<b
I just get a very problematic integral to solve at the end .
I made the substitution y/(x^3)=u p<=u<=q and y^2/x=v a<=v<=b but I can't get the result......
Last edited by G_Einstein (2010-10-17 01:51:51)
Se Zoti vete e tha me goje,se kombet shuhen permbi dhe,por SHqiperia do te roje,per te,per te luftojme ne.
God said that all nation exincts on the ground,but Albania will survive,for it,for it we are fighting.
Offline
Pages: 1