Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

What Is The Length Of Ad To The Nearest Tenth Of A Centimeter?

1)3.6

2)6.0

3)6.4

4)4.0

Please Explain. Thank You.

*Last edited by lakeheadca (2010-06-24 17:12:40)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

Hi lakeheadca;

Did you try to form your equations like this:

a^2 + x^2 = 6^2

a^2 + (10-x)^2 = 8^2

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.** **A number by itself is useful, but it is far more useful to know how accurate or certain that number is.**

**Online**

**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

6²+8²=c²

100=c²

10=c

10x=6²

X=3.6 Ans.

But Why 10x Multiplying With X???

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

That is correct,x = 3.6. I don't understand where you do not understand.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.** **A number by itself is useful, but it is far more useful to know how accurate or certain that number is.**

**Online**

**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

ADC∼CDB

AD/AC = CD/CB

x/6 = √(6² - x²)/8

Solve for 'x'

If two or more thoughts intersect, there has to be a point!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

You can subtract the top equation from the bottom one to get:

h^2 + x^2 = 6^2

h^2 + (10-x)^2 = 8^2 The h^2 will cancel when you subtract.

(10-x)^2 - x^2 = 8^2 - 6^2

100 - 20 x = 28

-20 x = -72

20 x = 72

x = 3.6

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.** **A number by itself is useful, but it is far more useful to know how accurate or certain that number is.**

**Online**

**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

ZHERO:

ADC∼CDB (One triangle looks bigger than other one????) they don't looks equal. Are you saying something about ratio

Bobby:

what is a² and what is h²

if (10-x) is AD

so DB should be 10+x or the same 10-x ???

lost again. hate Pythagorean.

*Last edited by lakeheadca (2010-06-29 03:30:53)*

Offline

**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

I think first time you guys came across someone who is that bad in Math

*Last edited by lakeheadca (2010-06-29 03:42:35)*

Offline

**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

Yea.. The triangles are "similar" and not "congruent".

Its means that all their angles are equal and their sides are "proportional".

If two or more thoughts intersect, there has to be a point!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

I think first time you guys came across someone who is that bad in Math

Calm down, I am worse. If I appear better, it is only because I have been doing it longer.

You might be getting a little confused over the fact we are using 2 different methods. Don't be. Just means you have a choice of what you like and understand best. Right now you are in school, your teachers are jamming many methods down your throat. They want you to learn all of them. When you are on your own you will get to choose what you like and are good at. I like simultaneous equations and solve many problems with them.

Bobby:

what is a² and what is h²

if (10-x) is AD

so DB should be 10+x or the same 10-x ???

No, If AB = 10 and AD = x then DB = 10 - x

a is side CD so I will out it into easier notation, sorry about the confusion.

1) (CD)^2 + x^2 = 6^2 Triangle CDA

2) (CD)^2 + (10-x)^2 = 8^2 Triangle BDC

Again 2 equations and 2 unknowns. If you subtract eqtn. 1 from eqtn 2 you will eliminate (CD)^2.

Can you now solve for x?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

**Online**

**lindsey8555****Member**- Registered: 2010-06-07
- Posts: 4

Archimedes run rings around your head? Well you've come to the right place. This is where you'll find almost everything you'll ever need to know about Geometry. We have a special page on constructions and plenty of sample problems to help you understand the concepts. Have a blast and don't forget to check out our Glossary - it's huge!

Offline

**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

Thank you Bobby. I got it. You made the problem easy.

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

Your Welcome!

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

**Online**

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

Hello allanmc0719

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

**Online**

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

Hi allanmc0719;

Sorry to hear that, hope you feel better.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

**Online**

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 104,193

No, not me. I hate resting. But if you must then...

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

**Online**

Pages: **1**