Give triangle ABC and EDC, c is the midpoint of
BD and AE.
prove: AB|| DE
∠ ACB = ∠ DCE (vertically oppsite ∠s)
AC/DC = BC/EC = 1/2 (given)
∴ ACB∼DCE (SAS similarity)
∴ ∠ABC = ∠DCE
AB||DE (alternate angles are equal)
If two or more thoughts intersect with each other, then there has to be a point.