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## #1 2010-04-04 22:42:59

ZHero
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Registered: 2008-06-08
Posts: 1,889

Last edited by ZHero (2010-04-05 19:31:17)

If two or more thoughts intersect, there has to be a point!

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## #2 2010-04-05 02:22:35

JaneFairfax
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Registered: 2007-02-23
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## #3 2010-04-05 04:03:09

soroban
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Registered: 2007-03-09
Posts: 452

.

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## #4 2010-04-05 05:37:58

ZHero
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Registered: 2008-06-08
Posts: 1,889

JaneFairfax wrote:

ZHero wrote:

Jane, can u tell me what does this N=-2 signify?? :

Last edited by ZHero (2010-04-05 05:44:09)

If two or more thoughts intersect, there has to be a point!

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## #5 2010-04-05 05:49:25

ZHero
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Registered: 2008-06-08
Posts: 1,889

soroban wrote:

NICE!!

If two or more thoughts intersect, there has to be a point!

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## #6 2010-04-05 16:47:56

Avon
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Registered: 2007-06-28
Posts: 80

ZHero,

You haven't really shown that (N+2)^2 = 0, only that (N+2)^2 is divisible by 9.
Hence N must be one of 1,4,7 and you'll have to do something else to decide which.

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## #7 2010-04-05 19:37:34

ZHero
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Registered: 2008-06-08
Posts: 1,889

Avon wrote:

ZHero,

You haven't really shown that (N+2)^2 = 0, ...

I just did my calculation above and got (N+2)^2=0.
I mean, I don't Want to Show that (N+2)^2=0.
I just want to know what information does (N+2)^2=0 hold??

If two or more thoughts intersect, there has to be a point!

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## #8 2010-04-05 23:43:28

Avon
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Registered: 2007-06-28
Posts: 80

When you replace numbers by their digit sums and cast out nines you are essentially considering two numbers to be the same if they have the same remainder when divided by 9.

I would write
rather that
when I am doing this. Hence we have

We cannot now deduce that

since 0 has three square roots modulo 9. These are 0, 3 and 6 so we have

and since I'm biased against negative numbers

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## #9 2010-04-06 00:37:33

ZHero
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Registered: 2008-06-08
Posts: 1,889

hi A1

Wonderful Explanation!!

Now i got it...

Thx a Lot!

Last edited by ZHero (2010-04-06 02:29:13)

If two or more thoughts intersect, there has to be a point!

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