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You are not logged in. #1 20091118 13:22:24
expected value for three out of six cards dealt!If each card has same points as their number (Ace is 1 point, 2 is 2 points, 3 is 3 points), the Jack, Queen, King each is 10 points...what's the expected value for the three highest cards out of six dealt cards? What's the expected value for the three highest cards out of eight dealt cards? (they're theoretical expected values) #2 20091119 04:23:05
Re: expected value for three out of six cards dealt!
[Who assigned it anyway? . . . Professor deSade?] . #3 20091119 11:11:44
Re: expected value for three out of six cards dealt!I have a feeling that we may be able to solve this without enumerating all the combination Maths is fun! #5 20091119 17:23:15
Re: expected value for three out of six cards dealt!hallo~ #6 20091119 18:23:11
Re: expected value for three out of six cards dealt!Hi mofaye;
This is a HIGH SCHOOL question? Oh, I get it, you already have the answer. So why are you posting in Help Me? I will withdraw my previous posts and answers and work on something else. Last edited by bobbym (20091119 19:19:40) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20091120 01:25:17
Re: expected value for three out of six cards dealt!Aah, sorry about mofaye... she's a bit...meh. We don't actually have an answer for it, since this is part of our DM project (and before anyone says it's cheating by asking here, I already asked my teacher and she said we're allowed to ask other people for help). I think what mofaye meant was we can't present to her the answer that's achieved from a simulation (because it's not part of our curriculum) and we need to show the break down of how to get each probability.... #8 20091120 08:45:11
Re: expected value for three out of six cards dealt!I'm REALLY SORRY!!! It's probably a misunderstanding in my sentence, what I actually mean is the question is super hard and we are not allowed to ask teacher, so it's pretty frustrated. #9 20091120 12:58:25
Re: expected value for three out of six cards dealt!Hi mofaye and froggy21; with a computer, this is the exact answer. as the expected value of the sum of the 3 highest cards dealt out of 6. As a check to the above work, I did an ordinary simulation of dealing out 6 cards 25 000 000 times: The simulation came up with an average value of 26.73757884 for the sum of the 3 highest cards dealt out of 6. This is very close to the exact answer. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #10 20091120 13:03:08
Re: expected value for three out of six cards dealt!Hi froggy21;
Soroban in post#2 already started that sort of analysis, take a look at what he has done .
I think he is correct. For these you would use the multivariable hypergeometric distribution. Last edited by bobbym (20091120 13:29:36) In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #11 20091120 18:26:33
Re: expected value for three out of six cards dealt!Aah, thank you very much for all your help! #12 20091121 00:16:49
Re: expected value for three out of six cards dealt!Hi froggy21; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #13 20140202 00:43:17
Re: expected value for three out of six cards dealt!
Finally the long awaited answer to this. I just realized that gAr when solving one of mine over in another thread has solved this one too! This agrees well with simulations. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 