Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2009-05-28 21:12:23

richard clark
Member
Registered: 2009-05-28
Posts: 1

For all you algebra buffs

I need to transpose a formula and my algebra isn't up to it.  I would welcome any suggestions or solutions.  the formula is:

S =  (A * (A + 1) * (A + 2))
       ---------------------------
                    6

I need to rearrange this and make "A" the subject of the formula.  I believe there is a method using sucessive approximations but I would prefer not to take this approacg. If anybody fancies a little bit of brain-bashing, please feel free.

Many thanks

Richard Clark

Offline

#2 2009-05-29 09:42:26

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: For all you algebra buffs

Algebra won't be enough.  You have the points A = 0, A = -1, and A = -2 all give the value S = 0.  This means the inverse (i.e. solving for A) won't be a function.  You can locally come up with approximations for the inverse where the derivative with respect to A is nonzero, but this is about all you can do.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

Offline

Board footer

Powered by FluxBB