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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

I just need a simple explanation for how horizontal asymptotes work?

and what makes slants?

Vertical asymptotes are just denominator equal to 0. to solve for x.

f(x)= (x+3)/(x-1)

V.A. x = 1

H.A. y = ?

No slant cause you cannot factor?

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**mathsmypassion****Member**- Registered: 2008-12-01
- Posts: 33

To find horizontal asymptotes you have to calculate the limits to + ∞ and - ∞. If any of them is a finite number, that's a HA. In your case, both limits are 1 so y = 1 is HA (to + ∞ and - ∞).

For slants: if a function does not have HA, it may have slants asymptotes.

For example: f(x) = (x^2 + 1)/(x + 1)

In order to find the SA follow the steps:

1. calculate the limit to +∞ for f(x)/x. If this limit if finite (a real number ≠ 0), let's call it m, than m would represent the slope of the SA. Go to step 2. If the limit is not finite , the function does not have SA to +∞. Go to step 4.

2. Find now the limit to +∞ for f(x) - mx and call this real number n.

3. The SA is y = mx + n

4. Do the same thing for -∞ . You might get a different asymptote.

*Last edited by mathsmypassion (2009-01-22 08:51:16)*

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