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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 23,297

1. Differentiate

with respect to x.2. Differentiate the following with respect to x.

(i)

(ii)

(iii)

3. Differentiate the following with respect to x.

(i)

(ii)

(iii)

4. Differentiate the following with respect to x:

(i)

(ii)

5. Differentiate the following with respect to x:

(i)

(ii)

(iii)

(iv)

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**glenn101****Member**- Registered: 2008-04-02
- Posts: 108

1.

I don't know any rules for calculus, I will be learning the quotient, product and all that next year.

So I've managed to solve all this with finding derivatives by rule and the binomial expansion:)

(3x^2-1)^3= (3x^2)^3 (-1)^0 = 27x^6

= 3(3x^2)^2 (-1)^1 = 27x^4

= 3(3x^2)^1 (-1)^2 = 9x^2

= 1(3x^2)^0 (-1)^3 = -3x^2

dy

-- (27x^6+27x^4+9x^2-3x^2)

dx

= 162x^5-108x^3+18x

*Last edited by glenn101 (2008-12-19 15:22:49)*

"If your going through hell, keep going."

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