Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,159

A contractor agrees to complete a work in 100 days. He engaged 140 men for the job and after doing the work for 60 days, he came to know that only half the work was completed. How many more men should he hire to finish the work in the agreed time?

Character is who you are when no one is looking.

Offline

**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

So, 140 men did half the work in 60 days, and the boss needs enough extra men to get the remaining work done in 40 days. So that means...[left for others]

Why did the vector cross the road?

It wanted to be normal.

Offline

**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,552

Approximately this many:

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

Offline

**tt****Member**- Registered: 2005-07-03
- Posts: 32

He should hire 70 more men to complete the work in agreed time.

Offline

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,159

Excellent! You are correct! Tell us how you did it!

Character is who you are when no one is looking.

Offline

**tt****Member**- Registered: 2005-07-03
- Posts: 32

The contractor needed 140 men X 60 days = 8400 man-days to do half the work. So he'll need 8400 more man-days to do the rest. He only has 40 days left, then he'll need 8400 man-days / 40 days = 210 men. He already has 140 men, so he has to hire 70 more men.

*Last edited by tt (2005-07-14 17:53:51)*

Offline

Pages: **1**