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**schinsammy****Member**- Registered: 2008-08-17
- Posts: 1

** 5A+BC--------- D43**

In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

If we take that A, B, C and D CANNOT take values of 5, 4 and 3 then we get (A, C) = (1, 2) or (2, 1) ; B=9 and D=1

Hence, A+B+C+D=13 !!

*Last edited by ZHero (2008-08-17 20:27:13)*

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

57+86 = 143 is another possible solution though, which would mean A+B+C+D=22.

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