You are not logged in.
Pages: 1
I need help setting up this problem so that I can solve it.
Mike has 2 more baseball cards than Jen. Then he bought 3 baseball card from Jen. Now how many more baseball cards does Mike have than Jen?
Thank You!
Offline
Mike - 2 = Jen is one way or Mike = Jen + 2, either way.
Then he got 3 from Jen
NewJen = Jen - 3 and so NewJen + 3 = Jen
NewMike = Mike + 3
See above how Jen lost 3, and Mike got 3 ?
Now you need to find out what is NewMike = NewJen + howMuch ??
NewMike = Mike + 3
NewMike = (Jen + 2) + 3
NewMike = (NewJen + 3) + 2) +3
NewMike = NewJen + 5 + 3
NewMike = NewJen + 8
So NewMike has 8 more cards than NewJen.
Last edited by John E. Franklin (2008-07-30 09:01:39)
igloo myrtilles fourmis
Offline
Also, just assign some value to Mike for purposes of example (let's say he's got 5). Now subtract 2 from that to get 3 (Jen's number of cards). Next, add 3 to Mike's number and subtract 3 from Jen's number. That leaves you with Mike having 8 and Jen having none. 8-0=8, so John's answer is correct.
Linux FTW
Offline
Pages: 1