Math Is Fun Forum
Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 2008-07-18 16:36:09
- Identity
- Member
- Registered: 2007-04-18
- Posts: 934
Integration find the shaded region
Find the region bound by the curve, the axes, and the line x = 1.
I don't know what I did wrong! I got the answer
but the answers say ?? ThanksOffline
#2 2008-07-19 11:02:46
- John E. Franklin
- Member
- Registered: 2005-08-29
- Posts: 3,588
Re: Integration find the shaded region
Did you do the definite integral between x=1/3 and 0 for the positive part,
and between 1 and 1/3 for the part below the x-axis?
igloo myrtilles fourmis
Offline
#3 2008-07-19 11:21:16
- John E. Franklin
- Member
- Registered: 2005-08-29
- Posts: 3,588
Re: Integration find the shaded region
I get this for both regions added together,
but I'm terrible at calc:
-1/3 + (4/pi)(sqrt(3) - 1)
approx 0.599
igloo myrtilles fourmis
Offline
#4 2008-07-19 11:23:01
- John E. Franklin
- Member
- Registered: 2005-08-29
- Posts: 3,588
Re: Integration find the shaded region
Google calculator says your answer is 0.599 also.
igloo myrtilles fourmis
Offline
#5 2008-07-19 11:29:15
- Identity
- Member
- Registered: 2007-04-18
- Posts: 934
Re: Integration find the shaded region
Thankyou John, that's the same as mine but in a different form... maybe the answers are wrong after all 
Offline
Pages: 1