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hi everybody ... please help me in solving this Q :
prove that if B ^ E = Ø and C U B = universal set and A ^ C = Ø then A ^ E = Ø .
note :
^ : intersetion
U : union
thanks in advance
Go by way of contradiction. Assume that there is an element in both A and E. Show that this means either B ^ E or A ^ C is non-empty.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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If X ^ Y = Ø, then X and Y have no common elements. Another way of thinking about this is that if an element in in X, then it can't be in Y.
If X U Y is the universal set, then X and Y between them have every element. In other words, if an element is not in X, then it must be in Y.
Now consider an element in A.
This element is not in C, because A ^ C = Ø.
Therefore, it is in B, because C U B = universal set.
Therefore, it is not in E, because B ^ E = Ø.
No element of A can be in E, and hence A ^ E = Ø.
Why did the vector cross the road?
It wanted to be normal.
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Thanks Ricky and mathsyperson ... my big mistake was :
if B ^ E = Ø
then B ^ E = B ^ B comlement
E = B complement ! ... thats really stupid
thanks alot !
[Dickinson]\mbox{Assume there is an element }x\in A\cap E.[/Dickinson]
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