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evaluate
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Why did the vector cross the road?
It wanted to be normal.
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Wow, looks like you cant even reverse the dy and dx, cuz lnx = ln0 is not define...kinda hard
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Unless you're taking complex analysis, you won't be able to solve this integral. And even if you are, I have a feeling it diverges, though I'm not certain.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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evaluate \int_{0}^{\frac{\pi}{2}} \int_{x}^{\frac{\pi}{2}} \frac{\sin y}{y} dydx
i made a mistake it's sin y/y not x
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evaluate
i made a mistake it's sin y/y not x
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Even with that, you aren't going to get an answer using elementary functions.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Last edited by Dragonshade (2008-05-18 07:54:53)
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The bounds of integration with respect to x would be y to pi/2, not 0 to y.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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The region should be the upper half of the rectangle divided by the line y=x, right? then I still think it should be 0 to y with respect to x
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Whoops...
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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