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Hi ganesh,
Hi leibgrangian,
This one is simple..
http://en.wikipedia.org/wiki/Methods_of_computing_square_roots
Refer decimal(base 10)
Hi ganesh,
Hi ganesh,
Hi Ganesh,
Hi ganesh,
Hi ganesh,
Hi ganesh,
Hi bobbym,
Problem #12:
An urn contains 15 balls. There are only 2 different colors the balls can have, red and orange. There are at least 3 of each color in the urn. Picking 3 balls without replacement. the probability that all of the picked ones are red is the same as the probability that exactly one of them is orange. How many of the 15 balls are red?
Hi bobbym,
No need of sorry bobby.. I need to thank you for posting wonderful probs.. Bobby, How about a starting a new topic on out of box thinking puzzles..?
Hi bobbym,
Okay.. Thanks anyways..
Hi bobbym,
Who eats the pie?
A,B,C,D and E decide to stop arguing and to do something together for a change. B's Mom bakes them a big pie to celebrate their togetherness. Before they start to eat they begin to argue about primes. They are mathematically inclined after all. They settle down on this one particular question.
If we start with the set of all fractions with 1 as the numerator and all the primes as denominators ( { 1 / 2, 1 / 3, 1 / 5, 1 / 7, 1 / 11, ...} and each of us starting with A and in order ( A,B,C,D,E, A,B,C,D,E... ) takes the next fraction and eats that amount of the remaining pie. In other words A eats 1 / 2, B eats 1 / 3 of the remaining half, C eats 1 / 5 of the remaining sixth... When we get to E and if there is more pie left we start again with A. The question is will we ever finish the pie?
A says) Since this can go on forever I think there will always be some pie left.
B says) Not necessarily sometimes an infinite process can equal a finite number. I think the pie will eventually be consumed.
C says) Who cares I am hungry.
D says) No wait, I think I read about something like this called Zeno's paradox.
E says) Hey D, did you make that up?
Hi bobbym,
Super easy!
Prove that:
Without using any particular value of sin(x) or cos(x).
Hi bobbym,
A real killer!
A man walks through a tunnel. Two thirds of the way through he sees a car heading for him. The car is moving at 75 mph. If he starts to run he can get to either end of the tunnel just as the car does. What is the speed in mph of the running man?
A says) Impossible! You have to know the distance the car is from the man.
B says) I don't think so, but I am unable to solve it.
C says) I solved it. It was easy. The man is moving at 25 mph.
D says) I agree with B. It can be solved but C's answer is wrong. But I can't prove it.What do you think?
Hi ganesh,
Hi ganesh,
Hi ganesh,
Hi ganesh,
Hi ganesh,
Hi Superlynx,
What you've done is wrong.. It's not putting numbers together rather its multiplication..
1x5x9-1x6x8-2x4x9+2x6x7+3x4x8-3x5x7.. and the answer is zero..
Bye friends.. Enjoy math..
And yes there are 4 or 5 of us running around.
This is wat is giving you an extra edge over others..
Hi bobbym,
It's 4:25 PM here.. A difference of 13.5 hours..
Hi bobby,
Yeah i saw it.. Thank you..
Hi bobby,
Wat time is it now in your country..?