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1. ax+by=c
I need to make a program that solves different diophantine equations.
Can someone help me?
For my new algoritm I should learn more about the diophante equations.
My conjecture is true.
Logic:
You are playing two chess games at the same time (first you move in the first, then your from the first moves then you move in the second then the second opponent moves and you get back to the first and so on)
Give a strategy (it's logical) when you are black in the first game and white in the second to be sure you'll get at least one point at the end.
I tried with mirror strategy but it didn't work.
Another question: why the scientists haven't revealed a strategy for the chess?
OK,Here is the answer direct from the original equation:
Sorry, santh, first time i didn't saw your last post. It's pretty good. And something interesting.
Conjecture:
Let p-prime.
Then for every k∈[1,p) there exist prime number q>p for such
q==k(mod p)
I'll test it using computer program.
I think you can't Bur wait for MathsIsFun.
Guess 6:9215
Oh, yes, sorry.
I don't have solution for n = 16... yet
I told you it will be ugly.
ax^3+bx^2+cx+d=0
Here's the real solution:
I'm close to next algoritm
{1,3,33,48}!!!
No comment.
It would be something very VERY ugly.
And probably it's complexity will make it useless.
I'll have a break.
{2,34,47}!!!
The chain
{1,24,120}
Max=120
So we dont have solutions for the following:
3,4,26,27
We have solutions for these lenghts:
2,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,28
Length: 6
MaxNumber: 19
sq(3,6)={3, 1, 8, 17, 19, 6}
Length: 8
MaxNumber:28
sq(28,8)={28, 8, 1, 3, 6, 10, 15, 21}