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  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#1353 Jokes » Proof women are evil » 2006-01-30 16:43:17

mikau
Replies: 3

This is utterly genius: http://www.funnies.com/proof.htm

#1354 Re: Dark Discussions at Cafe Infinity » Well done, Ricky » 2006-01-30 06:23:40

is that the same Ricky who hangs out here? yikes

#1355 Re: Help Me ! » why does the 5 square trick work » 2006-01-29 20:23:56

I didn't. Never heard this before.

#1356 Re: Introductions » knock the door ... » 2006-01-29 20:09:21

So what about your math background? Where did you study, got any goals for the future concerning math?

#1357 Re: Dark Discussions at Cafe Infinity » Year of the Dog » 2006-01-29 19:32:14

I'm in heaven! :-D I love the inscribed rectangles! I shall approximate the volume before devouring!

Time to InteGRRRRRREEEAT!

#1358 Re: Dark Discussions at Cafe Infinity » Year of the Dog » 2006-01-29 06:36:23

Yay! I'm a tiger! Give me a giant steak or I'll eat you!

#1359 Re: Dark Discussions at Cafe Infinity » Year of the Dog » 2006-01-28 14:27:35

I was born in 1986. With my luck thats probly year of the jackass.

#1361 Re: This is Cool » a program that searches for values of pi » 2006-01-28 12:07:59

siva.eas, I doubt we're gonna make any never before made discoveries here. We're just having fun.

#1362 Re: This is Cool » a program that searches for values of pi » 2006-01-28 11:57:36

Well just  wrote this program to use numerical integration of the area of a unit circle in the first quadrant, then multiply that by 4 to find pi. It works but using super large values of x seems to decrease the level of accuracy rather then increase it. Probably 'cause the values aren't being stored to enough decimal places and loosing their accuracy.

#include <iostream>
#include <math.h>

float f(float x);

int main()
{

float x;

float n = 200000;

for (int i = 0; i < n; i++)
{

 x += 1/n * f(i/n);

}


std::cout << "pi = " << 4 * x << "\n";

return 0;

}




float f(float x)
{

if ((1 - x*x) < 0) { std::cout << "error " << x << "\n"; return 0; }

return sqrt(1 - x*x);

}

#1363 Re: This is Cool » a program that searches for values of pi » 2006-01-28 11:10:32

In my oppinion it might be more interesting to write an algorthim to use numerical integretion to find pi by finding twice the area under the curve x^2 + y^2 = 1 and above the x axis. (the area of a cirle of radius 1 is pi.)

#1364 Re: Help Me ! » check my homework » 2006-01-28 11:05:32

What the heck is gradients? Oddly my mathbook never mentioned that term.

#1365 Re: Jokes » Plus C » 2006-01-28 07:19:02

lol. Good one. Yeah only a mathematician would understand. The absence of + C is probably the most common mistake made in calculus.

#1366 Re: Help Me ! » Just a simple problem? » 2006-01-27 16:07:02

What exactly are we trying to find here? All I see is desription, no question.

#1367 Re: Introductions » hi all » 2006-01-27 10:54:59

Math is power. At first it can be tedious but advanced math shows you how to levitate. Its awsome!

#1368 Re: Help Me ! » Son asked for help with trig identities.. can't seem to remember how » 2006-01-25 20:24:04

Yeah, just had to multiply above and below by cos x and we would have had it.

Wish I could ask my dad for help. He went as far as calculus 2 in college but never really had to use it, so he forgot most of it. What a pity...

#1370 Re: This is Cool » my gosh... » 2006-01-24 17:45:51

What about girls who are bad at maths? What do they get to help them pay attention?

Put a dollar sign in front of every number. That should do the trick.

#1371 Re: This is Cool » my gosh... » 2006-01-23 17:46:33

lol:lol::lol:

"today we are going to study the area under a curve...."

#1372 This is Cool » my gosh... » 2006-01-23 14:49:55

mikau
Replies: 17

If this site had a "this is not cool" forum I would have posted this there. Have you heard about this so called "bikini calculus" where they get these girls in bikinis to instruct guys in math so they pay attention? Do they really think guys will be looking at the chalk board?

Those who choose philandering over math should suffer the consequences!

#1373 Help Me ! » fundamental theorem of calculus part 2 » 2006-01-22 19:22:06

mikau
Replies: 2

Just read about this today. It stated that every continuous function has an antiderivative. My book then trailed off on something about integreting with a constant as the lower limit of integration. In the end I couldn't see there point, and they then simply said "we state the theorem without proof:"

I'm not sure what the point was. I reread it 4 times and couldn't quite see what conclusion it made. Now obviously, every continuous function encloses a certain area above and below the x axis, so some integral must exist.

But then it said some functions can't be integrated, like e^-2x dx. But the fundamental theorem of calculus garentees e^-2x dx has an antiderivative. Seems like a self defeating statement. If there is no function that can be differentiated to get  e^-2x dx, then how can it have an antiderivative?

#1374 Re: Help Me ! » limits » 2006-01-22 16:31:14

ricky is right. Thats the same thing I read. Like I said, by convention,  √x means the positive square root. Where as if you were to verbally ask for the square root, it could mean the positive or negative root.

But of course, if you have the expression x^2 = 4, you can take the square root of both sides but you must consider the postive and negative square root. x = +- √4     note! If √4 represented the positive AND negative square root of 4, then the +- signs would be uneccessary and redundant.

#1375 Re: Help Me ! » help me please.! » 2006-01-22 11:07:30

1)  Using the law of sines gives;

sinA/a = sinB/b;   since nothing varies but b this becomes;

A = arcsin[4sin34/b]

  a)  A = arcsin[4sin34/5] ≈ 26.574°

       The only other possibilities are (180 - A) = 153.426

   ....but 153.426 + 43 > 180, so this would not be a triangle.

   b) A = arcsin[4sin34/2] = which does not have a solution

   c) A = arcsin[4sin34/2.237] ≈ 89.181 and 90.819

      Therefore two triangles can be formed.

   d) A = arcsin[4sin34/3] ≈ 48.21 and 131.79

       Since 131.79 + 43 < 180 both angles above are possible.


So for this part, data c and d would produce two triangles.

I don't understand this at all, what does it mean by two triangles?

Also, forgive me if I'm wrong but you wrote: A = arcsin[4sin34/5] ≈ 26.574°    then        The only other possibilities are (180 - A) = 153.426

Uh.. thats two angles that sum up to 180. Don't triangles usually have three angles? I'm missing something here. Seems to me, the remaining angle should be 180 - A - 34.

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