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hi zee-f
the first one is correct,but the second one isn't finished.
you didn't solve x^2-4=0.
hi ganesh
hi ganesh
hi ganesh
hi ganesh
hi bob
yes you are right.you could express it in km but it wouldn't change anything cuz the stuf in kilometres cancels out.
but if the (10,10,10,10,10) is the same when the first two tens are flipped than shouldn't (14,6,30) be the sam as the triple with the first two flipped which is (6,14,30)
hi djohnstone3
welcome to the forum.
you are probably right but it would be nice if you could post the problem here.
so (10,10,10,10,10) would be diffferent from (10,10,10,10,10) because we can pay 1st 2nd and 3rd 10 to the first guy,or we could pay 1st 3rd and 5th ten to the first guy.that doesn't seem very logical if you write it as an ordered sequence.
hi
is (4,16,30) the same as (16,4,30)?
hi
so to pay them both out he could do it like this:(90,100)?
hi bobbym
see you finally solved it.what does the (20,30) mean?
hi ganesh
hi
actualy the value of x^x^x^x^...:
Let s=x^x^x^...
s=x^(x^x^x^...)
s=x^s
So once we can sole this equation in terms of x then we get the value of s.
hi john
first time i have seen you online as well.are you here often?
hi bob
yes they are mutually exclusive,but maybe he has something in between that he cannot describe any differently,or there is someone that is sometimes his enemy and sometimes his friend.
friends+enemies=frenemies.the best definition you will find.
ure welcome.i didn't understand it at first.
i think that if a polynomial can be factored by any other method than it can also be done by grouping.
hi safp7
welcome to the forum.Why can't you post links?
x^2-169=
x^2-13x+13x-169=
x(x-13)+13(x-13)=
(x+13)(x-13)???
hi bobbym
could 19 be done by grouping?
hi nevinsmith
i think it should be u=x and dv=(sinx)^3 dx
hi
because (x,y) is apraching (0,0) we can come to that point along any line that goes through that point.and because y=x satisfies that condition we can use that line to calculate the limit.
you can approach the limit from infinitely many sides,but just because two of them match upo doesn't mean that it exists.if you substitute y=x than you get: