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yup.because the RHS needs to be positive.
what then?
i tried to solve it in algebraic way.
it is not clear to me.i think i am dumbing out.
how did you get your answer?
sorry it is -√158
no i need it in a pretty form.
how did you get this solution?
is that square root of 158?
if that is not a plus or minus square root of a number that i think that you are wrong.
how did you get that?
no it isn't.
hi guys
i have in my hands the equation:
how do you solve this in the field of real numbers?
hi soroban
do you post here everything you post on MHF?
surely there are.that is a very good question.
every quadric equation can be factored,but only in a certain field of numbers.so you can factor x^2+2x+1 in the field of integer, rationals,or real numbers.but x^2+x+1 cannot be factored in any of these fields,it can only be factored in the field of complex numbers.
everything is correct.brilliant!
very good!!!
that is right
hi zee-f
no not -1,but 1
hi gAr
hi zee-f
when you find solution of x^2-1=0 it is the same as looking for those valus of x for which the value of y in the function y=x^2-1 is equal to 0.
the same with your problem.we have to find all values of x for which y=0.and because y=0 we have to search for intersections of your graph with the x-axis...(remember the ordered pair (x,0) is on the x-axis).
hi ganesh
this should be the graph of x^2+7x+12
hi ross.s
welcome to the forum!hope you like it here.
you can do this using the definitions of union intersection difference and complement of a set.
example:
x∈(A U B) if and only if x∈A or x∈B.