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I didn't know the best place to post this,
I don't understand the puzzle, I know what you've got to do: colour the cube in correctly using the two colours given, but I don't understand what the "see through" cube is or how that helps you. I do find things difficult to understand sometimes (I thought I had understood at some point but when I solved it using what I understood my answer was completely wrong) the instructions just don't seem to be complete enough
can anyone help?
I don't know if this has been asked (or even if I'm allowed to ask)
I once saw a post about how if you've been here a while you get the privalage of the "private message" feature. What cirscumstances are there for that?
perhaps another way to look at it:
not
bn opbn bn yuhjm,
First time!
wintersolstice wrote:you probably meant Q3? coz there are no Xs or Ns in Q2.
But for both the questionsI'm safe
Yes your right I'm meant Q3!
If you take the square matrix:
It's inverse is
Doesn't sound very interesting!
What about this?
consider this matrix
Now if
means the rth row and cth column element.now delete the rth row and cth column to make a n-1 X n-1 matrix find it's determinent and call it
in the below matrix
is represented byform the matrix
(the plus/minus sign is becuase you need to know the size of the matrix to know the sign of the bottom row)
In words what has been done:
change lowercase to capital (or from E to D)
start with the outer two elements which form diagonals swap the elements round (there's only one element in each so nothing changes)
go to the next diagonal pair (one inwards on either side) and swap them (the elements within the diagonal see above) and keep going
also the sign of the outermost diagonals stay the same the next pair change sign, whether the trailing diagonal (what all these diagonals are parallel to) changes depends on the size.
Calculate the determinent Δ in the following way:
(multiply the first row of original matrix by the first column of the new matrix)To find the detiminent of the n-1 X n-1 matrices use the above method (which means looking at n-2 X n-2 matrices and so on down to 2 X 2 whose determinent is above
if you put say that the determinent of a 1 X 1 matrix is its one element (which means the method above dosen't work on 1 X 1)
then for the 2 X 2:
then right:
and sustitute
which fits the above
using this method you can find the inverse of a n X n matrix provided you know how to do the n-1 X n-1 (you just have to work your way backwards to the 2 X 2
unfortunatly I don't know how to prove it!
What puzzle are you talking about, where is it and how am I supposed to know the answer to either of these questions... please.
It's on the "Mathsisfun archive" here:
http://www.mathsisfun.com/puzzles/marble-mix-up.html
Ibut nobody seems to have a clue about your puzzle: could you give a bit more info?
Basically using the info about who knows what's in their container (the colour of their third marble) in this case KKD (meaning that the first two knew what was in their container, the other person didn't, refering to the first three of course, this is the "situation" of the original puzzle, if you want to have a look and see what I mean) the puzzle has one unique solution.
However if you changed it to another "situation" such as KKK (as in the first three knew what was in their containers) the puzzle becomes impossible (there's not sufficient information to figure out what's in each container, because there's more than one answer) but one "situation" (apart from KKD) does have a unique solution (for what's in each container)
My question is: what "situation" apart from KKD creates this unique solution (obsviously not KKK) and what is the unique solution (what is in each container)
I hope that makes sense
I like your avatar of 5 intersecting cubes
I actually got the picture off Wikipedia it was an orthogonal projection of one of the Hess-Schlafli polychora, I didn't know it was also a picture of the "compound of five cubes"! Although I've heard of that shape:D
for those who have done this puzzle, here's an extra: if you change what the others knew about their containers, in only one situation can you still solve it. In that situation who knew and what is the solution?
I've recently been doing a search for these (A polychoron is a 4D polytope made up of polyhedra, like a polyhedra 3D made up of polygona)
The properties are:
1) Strictly-convex from body to cell (this is generalising it to higher dimensions)
2) Non-vertex transitive
3) Regular faced
I found 193 of these so far and hope to find more
They're based on the Johnson Solids
[NO THERE ISNT!!
Thanks for that "Jane":D. Now I know who to ask if I ever get stuck again:cool:
You certainly live up to your usertitle: "Lengendary Member"!!!
I was thinking "level 3 of Cubilius" is Impossible I think there's a flaw in that game!
I made a few maths jokes based on the 3 trivial regular polytopes:
1) Q. Why did the cube drink a load of coffee?
A. Because it wanted to be a "hyper-cube"!
2) Q. Why did the "measure polytope" marry a "cross polytope"
A. She was a jewel (dual) (this might not make sense to some people!)
3) person 1: what's the opposite of a simplex
person 2: a complex
person 2: no a simplex! It's self-dual
what do you think?
You'd also need to show that 81n < 10^(n-1), for n ≥ 4.
That's not a problem though.
Thanks:D I knew my proof was a little incomplete, I just wasn't sure was else was needed
Actually yes they can!
y=∞x+c LOL
There is a simple prove to this.
Firstly
This means that a number will always go under 4 digits and loops can only contain numbers between 1-3 digits.
So test all numbers (proof by exaustion) below a 1000 and that's the proof
Here's a higher dimentional analog (if the original puzzle could be regarded as 2D, this would be 3D) When I can figure it out I'll see if I can do 4D!!!
If it doesn't make sense, you have 42 rectangles (of chain links) 3x5 and you have to build a torus which contains 18 rings each containing 35 links.
this is one of the easiest of this level, plus I came up with the idea of higher dimensional analogs myself.
Hope this might be more enjoyable
Please post if you have any questions
Edit: I've just spotted a mistake, (I didn't try and solve it first!) change the number of rectangles from 42 to 144.
OH yeah and change the torus to 36x60 (not 18x35)
I have done a short essay on Learning Mathematics
I would really value everyone's ideas on this subject.
How do you learn mathematics?
What works best for you?
What would you advise to others?
Not this is important but on the link for patterns, where it has the 8 semi-regular, one of them is chiral (it's mirror image looks different!) in this case the first one.
I read a lot of books and went on the internet and spent hours doing maths problems, just investigate ideas.
I've been trying to figure out why this shape is not uniform. All it's vertices have 3 squares and 1 triangle (if I've got that right)
"as there are pairs of vertices such that there is no isometry of the solid which maps one into the other. Essentially, two types of vertices can be distinguished by their "neighbors of neighbors."
This is the only clue I have but I don't know what it means. Can someone explain it to me?:D I would be most grateful.
I did try and make a formula for relating the "Depth" "lenght" and width of a "catenery" using the fact that it's
but I hit a snag! I'm not giving up that easy though.PS sorry I just can't find the code for "hyperbolic trig fuctions" or haven't they been added yet? And I'm still struggling with the code
wintersolstice wrote:When I can I'l post a higher dimensional analog.:D
I'm sorry, but I don't know what that means (my maths knowledge is only Year 4 high school level
). You'd have to keep it pretty simple for me to understand it, or include some explanations of any advanced concepts.
well I was going to post a very simple higher dimensional puzzle anyway, and to help people get the hang of it I'll give an example of a solved puzzle:D
OH and I'll post a picture to go with it
Hi wintersolstice,
I think I've worked out a formula for solving medium-level problems that commence with "1":
That's absolutly correct:D Although my method was slightly different, but I still used triangle numbers.
When I can I'l post a higher dimensional analog.:D
I posted the answer to the first in "Soroban"'s thread and I give you the answer to the second: 88
just break up 12 chains that add together to make 88 and put them between the remaining 88 chains!
So see if you can solve the 3rd
Ask if you want to to give some advice on solving them.