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the boundary in the complex plane is approximated by
an ellipse.
What does it mean ? Can any one explain me via figure .
Thanks
Fouier Descriptor representation has an great advantage . It reduce a 2D to 1D problem ./ How ? what does that mean actually ?
Does it mean Fourier Descriptor ( that are actually defined by complex numbers ) define 1D function ?
smaller the fourier co-efficient : lose of details and global shape of boundary of an object .
higher the Fourier co-efficient : more details and high frequency components .
these descriptor retain the principal shape feature of the original boundary . How can last figure( see image in below link ) retain the original shape although the number of Fourier co-efficient are less say M < N where N = total boundary points . ?
Note
Attached Image Link : http://imageshack.us/photo/my-images/85/44022547.png/
Thanks
Are groups used for translation , scaling , mirrored and rotation. if so then how? can any one please explain me via an example .
Thanks
speed should be calculate in integer or double or float ? ??
Please tell me with reason thanks
Actually , i have moving objects presented in video . i calculated distance . I need to find speed . I am thinking that where should i add statement to get time and use it for speed calculation,. for deciding that i need to understand time meaning w,r,t code.
Well could you please tell me that how are u say : 137809 is 137 seconds and 809 milliseconds. ?
Hi model;
That is not your exact output, what happened to the 123456?
Also 137809 is 137 seconds and 809 milliseconds.
Something is not right but GetTickCount() is incremental so if two of them are the same that means 0 time occurred between two lines.
ahh hy 123456 is inside cout just for showing some output .that is not time .
Hi ,
I get the time of each line of code of my program .
Program :
cout<<" timeBeginPeriod : " << timeBeginPeriod(1) <<endl; //Add Winmm.lib in Project
cout<<" start Time : " << ( (double)GetTickCount() )/1000<<endl;
cout<<" Hi "<< ( (double)GetTickCount() )/1000<<endl;
cout<<" Hi , 123 456 "<< ( (double)GetTickCount() )/1000<<endl;Note : GetTickCount() give me number of milisecs . ./
And i get this
timeBeginPeriod : 0
start Time : 137809
Hi 137809
endTimer : 0Which mean , each line of code taking time " 137809 " in secs .
My question is What does mean by 137809 . Does it mean its taking that its taking 17 secs and 809 milisec ?
I think its means 20sec and 809 milisec . Right ?
if so that mean in c++ each line of code take 20 secs and 809 mili secs . hmmmm ............
Hi ,
I get the time of each line of code of my program .
Program :
cout<<" timeBeginPeriod : " << timeBeginPeriod(1) <<endl; //Add Winmm.lib in Project
cout<<" start Time : " << ( (double)GetTickCount() )/1000<<endl;
cout<<" Hi "<< ( (double)GetTickCount() )/1000<<endl;
cout<<" Hi , 123 456 "<< ( (double)GetTickCount() )/1000<<endl;
Note : GetTickCount() give me number of milisecs . ./
And i get this
timeBeginPeriod : 0
start Time : 137809
Hi 137809
endTimer : 0
Which mean , each line of code taking time " 137809 " in secs .
My question is What does mean by 137809 . Does it mean its taking that its taking 17 secs and 809 milisec ?
What's a logic to find the most repeated value in the sorted data set .
Say dataSet = { 1 5 5 6 6 7 9 4 }
What's logic to find mod in the above data set . ??
How does Minimum perimeter polygon(MPP ) Algorithm work?
Can some one please explain me thanks
Hi model;
I do not understand your question. What kind of patterns? Do you want to fit equations to the data? Like a regression analysis?
Hi ,
pattern making like tree diagram .. or in form of set pair.
I have DAta base that having three features average , standard deviation and variance of 10 image which in arrays looks like this
Average standard Deviation Variance
63 12192 110
63 12103 110
64 12258 110
73 13331 115
88 14740 121
69 12937 131
79 13824 117
63 12192 110
65 12207 110
I have to make patterns .. Of these values . Mathematically it seems to me difficult .
but i think i should apply nested loop . and make patterns .
and then test my input image statistic with the patterns that we can get using nested loop . .
Is there a simple way in maths to get patterns of the above values .
Please help me Thanks
hy Bobby . I need mathematician like you .
I created group on face book . https://www.facebook.com/groups/Maths.GIS/
Can you please join that . so that i will be happy to post questions there.
thanks
I use geogebra. It does it all and it is fun!
Ohh , That's so cool and really a fun . ..
Thanks ..:)
ahhan yes . its clear to me now .
Bobby, Which tool do you use to make graph like above you posted ?
hmm ok thanks . .
Really thanks . i hope i disturbed you alot . actually there is much confusion in mind. sorry
Okay. I will need time to work on it now. I will post the solution and a method as soon as I get it.
hmm ok thanks . .:)
Really thanks . i hope i disturbed you alot . actually there is much confusion in mind. sorry
bobbym wrote:I have to be sure here! 5 points between A and B all equally spaced?
yes yes but , Is that depend on me for equally spaced decision , will that effect to more accuracy or good result . like more equally space . more good result .
so . the equally space decision depend on me ?
I have to be sure here! 5 points between A and B all equally spaced?
yes yes
Yes, do you want to place 10 equally spaced points between A and B? Do not even think about B to C yet. We are only on the first step.
hmm ok sorry , well for5 points equally spaced
You want to put how many points between A and B. All equally spaced?
hmm ok from 5 points for equally spaced .
You want to put how many points between A and B. All equally spaced?
yes right
model wrote:bobbym wrote:Hi;
The way to solve any problem is to stop thinking of it as a whole. They are usually too hard and too big to hold in ones mind. Be like a computer, one little step at a time and soon the whole job is done.
One point at a time. What would you like done between A and B in the diagram?
hmm well , again equal distance .. between A and B. and this distance should be same between B and C . and so on . .
hmm . well i am getting you step by step point . .:)
because i think we need to find the distance between all edges and then we can decide what should be the distance that would be equal in between edges .
Ok please continue. I must finish it ,
bobbym wrote:Hi;
The way to solve any problem is to stop thinking of it as a whole. They are usually too hard and too big to hold in ones mind. Be like a computer, one little step at a time and soon the whole job is done.
One point at a time. What would you like done between A and B in the diagram?
hmm well , again equal distance .. between A and B. and this distance should be same between B and C . and so on . .
Hi;
The way to solve any problem is to stop thinking of it as a whole. They are usually too hard and too big to hold in ones mind. Be like a computer, one little step at a time and soon the whole job is done.
One point at a time. What would you like done between A and B in the diagram?
hmm well , again equal distance .. between A and B.