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#76 Re: Help Me ! » Triangle funnes agggh » 2014-01-16 20:55:46
Oh thanks Im so stupid I thought something was wrong with the problem! Thx so much
#77 Re: Help Me ! » The diagonals of a quadrilateral » 2014-01-16 20:54:25
a math book AOPS geometry I am really bad at geometry 
#78 Re: Help Me ! » The diagonals of a quadrilateral » 2014-01-15 16:37:22
nah thats the exact problem
#79 Help Me ! » Triangle funnes agggh » 2014-01-15 14:13:33
- thedarktiger
- Replies: 3
In the triangle shown, n is a positive integer, and \angle A > \angle B > \angle C. How many possible values of n are there?
theres a figure but im new so I cant post wahh 
The sides are AB = 4n-9, BC = 3n+4, AC = 3n+1.
I figured out BC is the biggest and AC is second and AB is third biggest. pls help. thx a ton!!!!!:D
#80 Help Me ! » The diagonals of a quadrilateral » 2014-01-15 13:53:35
- thedarktiger
- Replies: 7
basicly I have all the lengths of a quad and I need to find the diagonal.
heres the problem:
The distance from Capital City to Little Village is 660 miles. From Capital City to Mytown is 310 miles, from Mytown to Yourtown is 200 miles, and from Yourtown to Little Village is 150 miles. How far is it from Mytown to Little Village?
no answer just please explain how to do this. You guys rock!
-the dark tiger
#81 Re: Help Me ! » pentagon problem » 2014-01-12 20:09:18
nice! thats correct! I wish the thing I'm doing had solutions
#82 Help Me ! » pentagon problem » 2014-01-12 17:41:44
- thedarktiger
- Replies: 5
In pentagon ABCDE, BC=CD=DE=2 units, <E is a right angle and m<B = m<C = m<D = 135 degrees. The length of segment AE can be expressed in simplest radical form as a+2sqrt(b) units. What is the value of a+b?
This is actually a lot of 45 45 90 triangles!
a+2*sqrt(b)
A xxxxxxxxxxxxxxxxxxxxxx E
x x
x x 2
x x D
n x 2 x x
x x x sqrt(2)
B xxxxxxxxxxxxxxx
C sqrt(2)
2
Then I drew BE and got that BE = sqrt(2(2+sqrt(2))^2)=sqrt(2)*(2+sqrt(2))
Then <ABE is 45 so ABE is 45 45 90 so AB = BE so AE = sqrt(2*(sqrt(2)*(2+sqrt(2)))^2) = 4*(2+sqrt(2)) = 8 + 4*sqrt(2) = 8 + 2*sqrt(8)
so the answers 8+8=16
whats wrong I got it wrong
:(:D
#83 Re: Help Me ! » Geometry problem » 2014-01-11 22:29:02
Thanks guys! actually you don't have use trig, the triangles are 30-60-90, so sides are 2:1:sqrt(3)
Thanks a ton! wouldn't have got without ya!
I got that too bobbym.
#84 Help Me ! » Geometry problem » 2014-01-11 19:34:15
- thedarktiger
- Replies: 5
In hexagon ABCDEF, AB = DE = 2, BC = EF = 4, CD = FA = 6, and all the interior angles are equal. Find the area of hexagon ABCDEF.
I cannot find any theorems or anything for that area...please explain...AND THX 
#85 Re: Help Me ! » Difficult geometry prob » 2014-01-11 17:31:41
Hi,
thanks a ton I got 433 (how to hide?) after you guys I was clueless!
EDIT:
im a bob to im robert!
#86 Help Me ! » Difficult geometry prob » 2014-01-10 19:50:53
- thedarktiger
- Replies: 8
Hi,
ABCD is a square. Parallel lines m, n, and p pass through vertices A, B, and C, respectively. The distance between m and n is 12, and the distance between n and p is 17. Find the area of square ABCD.
Im trying to post an image but it wont let im new 
thanks I spent I couple hours on this and have no idea.
-thedarktiger