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#903 Re: Help Me ! » What values of x make this expression a perfect cube? » 2014-06-10 05:32:27

I have no idea who is talking to whom anymore.

Thanks, Bob. I am pretty sure that you would've got it if you continued.

#906 Re: Help Me ! » What values of x make this expression a perfect cube? » 2014-06-10 05:22:17

Done. There might be mistakes though, so there may be more solutions.

#907 Re: Help Me ! » What values of x make this expression a perfect cube? » 2014-06-10 05:11:15

I do have a method. I will post it here. As Bob would always say, watch this space.

Solution

#909 Re: Introductions » Hi there » 2014-06-10 05:04:58

Hi jamesbailey1990 and kdipakj

Welcome to the forum! smile

#910 Re: Introductions » hello » 2014-06-10 05:03:44

Hi she taco

Welcome to the forum! smile

#918 Re: Help Me ! » What is useful to memorize? » 2014-06-10 03:56:26

bobbym wrote:

Can you immediately tell me what they equal? I bet you can, that means you have seen them so much you have memorized them. Why wait?

7^3, no. 11^3  neither, but I can calculate that one pretty quickly in my head.

I agree on 6^3, though, because everyone who does even a little bit of combinatorics will see that number.

10^3 is pretty straightforward.

#919 Re: Help Me ! » conditions required » 2014-06-10 03:53:18

Well, I really don't think that's what he's looking for right now. smile

And, aren't you missing a term there?

#920 Re: Help Me ! » What is useful to memorize? » 2014-06-10 03:51:33

I agree on 6^3. I'm not sure why you would need 7^3 and 11^3, though.

#922 Re: Help Me ! » conditions required » 2014-06-10 03:21:24

For a quadratic to always be positive you need:


and

For a quadratic to have positive roots, you need the conditions Agnishom posted, except, the second condition should be

#925 Re: Help Me ! » Square root algorithm » 2014-06-07 00:02:38

Hi Bob

I'm guessing he's referring to this one

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