Math Is Fun Forum

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Hi mantastrike,
Have a look at this page http://en.wikipedia.org/wiki/Rule_of_product
Also see the rule of sum.

Hi bobbym,
I wish you good health. Get healthy soon!!!!!

Hi Killbox,

I stumbled upon this while searching the net http://math2.org/math/constants/gamma.htm

Hi Bobbym,

It think it is possible. But you will have to prove it logically. Try it. Try to see the behavior of C(n) graphically for n = 2,3 and then a bit larger.

Come back if you have any problem.

Hi killbox,
I shall show you one of the approach.
Plot a rough graph of y = 1/x. Now you know C(1) = 1. C(2) = 1 + 1/2 - Log2. Note that Log 2 is the area of the graph 1/x from x = 1 to x = 2. and 1/2 is the area under y = 1/2 from x = 1 to x = 2. Thus Log2 > 1/2. Second term is less than 1. Apply similar approach for C(3)

Thank you Bobbym,
I have downloaded the first book Combinatorial Mathematics for Recreation - N. Vilenkin.
I will read it and post any doubts that I have on this forum.

Hi Bobbym,

Thank you so much for your time!

Hi Bobbym,
In your diagram, n = length of segment BP1 & n = length of segment BP3 are the only solutions for probability = 41.7/360. This is what i think. Am i right?

Hi bobbym,

I am confused. I do not understand your statement although it appeared correct to me till yesterday-

This is what i think ---- for probability p = 1/6 there will be only one solution n = sqrt(3)
and for a fixed probability p < 1/6 there will be exactly two solutions.