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#575. What is the value of x?
lol Nevermind. I read the problem wrong.
#593. What is the name of the longest chord in a circle?
Diameter, I say.
589. Leibneiz
590. Galileo
591. Chile
592. Saudi Arabia
Welcome, plutoman.
who is that on your pic iheartmaths? albert einstein?
Yup, that's correct, lego.
I'm from New Orleans, La, and I'm, uh, I'm still here.
iheartmaths wrote:Funny enough, I was working on this the other day. Being the amateur that I am, I had no idea this already existed. I was fairly certain someone had done this already, but I wasn't sure of its name. Sure enough, I came up with the same: n(n + 1)/2
What approach did you use to come up with that. I ask, because I too played around with that before I knew that some else already had (although I assumed someone did, I just thought it to be more fun on my own).
I drew out the diagrams of the triangles and realized that the number of dots is equal to the sum of the bases of every preceeding triangle. Obviously, that wouldn't be practical for the larger triangles like base 2000. So, the second thing I noticed was that as the base increases by 1, it shares a relationship to the total number of dots that increases by 0.5
1 = 1
2 = 1.5
3 = 2
4 = 2.5
5 = 3
So, a triangle with a base of 1 will have 1 dot. But a triangle with a base of 2 with have 3 dots. I know I'm terrible at explaining this.
So, naturally from that I got that the answer should be something like n (number) * d (decimal, .5, 1, 1.5, etc.). The obvious problem is that when you get to numbers like 2000, it's harder to predict what the number to multiply by is. So, I needed another forumla. Which I soon found that (n + 1)/2 gave me that. Then I just combined the two into n((n+1)/2). and it would look something like this, which makes the relationship a little easier to see:
1 * 1 = 1
2 * 1.5 = 3
3 * 2 = 6
4 * 2.5 = 10
5 * 3 = 15
Sorry, I know I don't do the best job at explaining, but I try, I try.
I'll be 20 in July. I'd give anything to be able to go back with the knowledge I have now and learn everything I missed because of my apathy towards schooling.
Funny enough, I was working on this the other day. Being the amateur that I am, I had no idea this already existed. I was fairly certain someone had done this already, but I wasn't sure of its name. Sure enough, I came up with the same: n(n + 1)/2
Hi,
I've browsed around these forums for a few days now and decided I'd sign up and contribute the little that I can. My math history is similar to an episode of one of those mid-day talk shows where you find out that the father is actually the uncle of the nephew's son-in-law, twice removed. Actually, what I mean to say is that math and I haven't always been on such clear terms as my name would suggest. It's quite a long and boring history. But to sum it up, I began loving math when it was too late (and by 'too late' I mean too late to go back and re-learn things in school. You know, math is cumulative, and all that jazz). Now I'm a freshmen in college, and my foundation in mathematics isn't exactly solid. Which is partially why I'm here, as well. I've taken to going all the way back, and I mean all the way back, to re-learn the basics.
I should clear something up, however. I've never been terrible at mathematics. But I feel as if I'm only mediocre because of my previous non-chalant study habits concerning math. So, being who I am, I feel it's my duty to learn what I should've learned so long ago. My ultimate goal is to graduate with a degree in mathematics, and to move on to graduate school, where I can obtain my Ph.D. That's far away, and for another day, though. So, hopefully, I can learn some new things here, contribute, make a few new friends, and have fun in the process.