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#26 Re: Exercises » Play with numbers » 2009-04-03 18:35:10
ohh dun worry brother ... if i have ne prob i say directly ... and if i feel someone stupid i say it to his/her face ... i dun care who he/she is ... few exceptions are people i respect ... and by no way i feel this girl falling in the "exception" category ... u r talking as if she is the math teacher out here ... let me tell u one thing dude .... her ways are very formula oriented and generally comes from people who are bookish in nature ... i dun care who u ppl are in this forum ... and i dun give a $bit$ to what u ppl care ... to me "what is right will remain so and what is wrong i ll try to correct it or despise it "
#27 Re: Exercises » Play with numbers » 2009-04-03 18:00:16
@jane ... sometymes u need to be good in english to solve math problems ....
u shud interpret the prob properly by understanding what is written ..... use ur brains .... not ur math laws 
..... btw math states only one law "logic" .... if u aren't good in that ... u lll remain as stucck to formula etc. as u currently are 
.....
#28 Re: Exercises » Janes Exercises III » 2009-04-03 17:47:58
@jane ... if my solution is wrong i will accept that before even u can tell me about it .... but if i am right ... u need to accept it ... there are no old ways in math .... u only accept some new ways if u think it is better than the previous one .... but in no way i can find your solution way better than mine 
... both of us used contradiction to solve it ... so how can mine be old ... infact u used the old way of squaring both sides etc. the one we used to do in schools ....
so in my books ur style of solution is in no way nearly as interesting or nearly as appealing as mine ...
oh yes ... as u say my solution is wrong ....
tell me one step which is wrong ....:lol:
if u can't show one such step ... never again say someone wrong 
#29 Re: Exercises » Play with numbers » 2009-04-02 21:23:01
yepp now u r rite ... 
#30 Re: Exercises » Janes Exercises III » 2009-04-02 21:20:07
@jane ... prove me 1+1=2
#31 Re: Exercises » Janes Exercises III » 2009-04-02 21:17:27
hahahaha ... u really know just one way to prove a prob and think that it is the only way ... let me tell u dear ... there are more than 5 ways to solve any problem in math
#32 Re: Guestbook » vote for your fav subjects » 2009-03-31 22:59:30
well u see my signature rt ??
#34 Re: Exercises » Janes Exercises III » 2009-03-31 21:36:26
well logically it is understood ... ....
#35 Re: Help Me ! » Probability » 2009-03-31 21:25:36
well no takers ????
#36 Re: Help Me ! » how to work out average » 2009-03-31 20:31:53
average shud always lie between the max and the min number ..
#37 Re: Exercises » Play with numbers » 2009-03-31 20:18:52
ganesh,
#38 Re: Exercises » Play with numbers » 2009-03-31 18:36:27
@ganesh ... answer is incorrect .... further post ur approach ... no need to post the solution just the approach .... look for the hint dude ...
#39 Re: Exercises » Janes Exercises III » 2009-03-31 18:34:43
@9 ... done
#41 Re: Exercises » Play with numbers » 2009-03-30 19:50:43
#6
I am a three digit number.
I am divisible by 3 or by 5.
I am divisible by 4 or by 6.
I am divisible by 5 or by 7.
I am divisible by 6 or by 8.
I am divisible by 7 or by 9.
I am divisible by 9 or by 11.
What am I?
#42 Re: Exercises » Play with numbers » 2009-03-30 19:14:34
@jane ... 
#46 Re: Exercises » Janes Exercises III » 2009-03-30 17:30:10
@jane ... how to use the hidden text ??? some html codes reqd if so give the name of the starting tag ... btw i was going o use 7k-1 and 7k-2 instead of 7k+6 and 7k+5 .... but somehow didn't
#47 Re: Help Me ! » finding the missing side of a triangle » 2009-03-30 17:25:44
opp = opposite
deg = degrees ....
now does that make me clear ?? it was english dude ... just few short forms which i thought any person with a min IQ will understand
ohh btw ,
min = minimum
IQ = Intelligence Quotient
:rofl
#48 Re: Exercises » Janes Exercises III » 2009-03-30 00:34:41
why has no one tried #1 ???
newayz ...
we can rewrite the equn as ... (n-2)(n-1)(n²-2)(n+1)(n+2)
we can clearly see that this expression will be div for n= 7k+1,7k+2,7k+5,7k+6 ... as in each of these casesone of n-1,n-2,n+1,n+2 ... contributes a factor of 7
for 7k+3 and 7k+4 we can find, by substitution, that n²-2 donates a factor of 7.
hence the expression is div by 7 ...
now, if n-1 and n+1 are even and as they are consecutive nos. we can write them as ... 2a,2a+2
now, 2a*(2a+2) = 4a*(a+1)
now a(a+1) will be div by 2! hence div of 8 is also true when n-1 is even
now if n-2 is even ... so is n²-2 and n+2 ....
3 even nos hence three multiples of 8 ... hence div by 8 ....
thus the exp is always div by 56 ...
#49 Re: Help Me ! » Second problem not for nervous » 2009-03-29 20:38:37
http://eqworld.ipmnet.ru/forum/viewtopic.php?f=3&t=143
u need some revisions on the definitions of derivatives dude ...
the step 2 which u have derived from step 1 in eqworld .... is math .... please understand the definition of derivative ...
for example ...
u have taken square and its perimeter as a base to derive .... (y)' = 2√y
i can derive from a cube and its surface area to derive ... (y)' = 3* y^2/3 ..... now which one will u follow ???
here is the proof similar to urs
if 'a' ia side of a cube ....
then a³ is its volume
now (a³)' = 3a² , which is half the total surface area ... and proceeding in ur manner .. substituting y=a^3 ... we get (y)' = 3* y^2/3
NOTE : if u substitute y = p² ... as u have done
then (y)' = 2pp'
= 2√y * (√y)' = 2√y / 2√y = 1 ..... this is the mathematical proof
#50 Re: Exercises » Play with numbers » 2009-03-29 18:50:03
i forgot giving a hint for #4 .... here it goes
try this figure.
A D
B G E
C F