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Are you sure it is not correct?
What kind of work?
I don't think that is possible here.
Have an example?
I am getting
I see, thanks.
In anything. But I prefer combinatorics.
Yes, but soon I won't have time to relax. I need to do more problem.
I haven't been doing almost any maths for the last three or four months.
Why? I'd really like to get back into form.
Great. Any new ones?
It can, but both methods are easily adjustible.
It would mean something is wrong. But since I'm vry lazy, I will just take your word on this one. That matrix is huge.
The matrix is easy to find, so that isn't a problem. What is the next one?
Yes, but you did not ask for one.
Wouldn't a Markov chain be quite big here (15 entries).
Why do you not want to move it?
Okay, so for numbers 1-10, we can use the recurrence. Then for 11-14, we use:
I'm not sure what you are asking.
See you later.
At least you now have your feet on the ground.
Long term probability?
When I first heard that joke, I just couldn't help myself. My laughter was of seismic proportions.
p[-4] = 0;
p[-3] = 0;
p[-2] = 0;
p[-1] = 0;
p[0] = 1;
p[n_] := p[n] = 1/5 (p[n - 1] + p[n - 2] + p[n - 3] + p[n - 4] + p[n - 5])
p[10]Yes, I did.
Okay, so for numbers 1-10, we can use the recurrence. Then for 11-14, we use:
Oh, but it will. I will explain, I just need to eat.
I have already fixed it.
So, those are correct?