You are not logged in.
Yes, please. !
Here :
An aleatory experience consists of turning an arrow on a roulette two times. (3 triangles, 1 circle, and two hexagon)
Question : What is the probability of obtaining exactly one haxagon.
i think im gonna re read the problem... im not sure of even understanding what they want ..ty for your help
it gives 16/36
but i still don't understand the logic behind it how did you get those numbers ?ty
ok...
explain this
oh
ho
oo
hh
yes. and what do you mean by simplest ideas ?
Could you explain me how you did it ? I get 12/36 and not 16/36....
hi
If I have the 1 circle, 3 triangles and two hexagons and they're in a bag and pick them two times with return what is the probability of getting exactly one hexagon ?
I get 3/9 but the answer is 4/9....
help pls thanks
Sorry Bobbym, Ive got other to finish. Il try it on my own, Im feelng that Im lacking knowledge in algebra, maybe I should do a review ^^
*b 1/a= 1b +2 *b
b/a=+2
Foget my question, heres my answer b=2a
Im trying to isolate b on the right of the equation, but must I also distribute the B to the whole right side of the equation ?
*b 1/a=1/b+2 *b (to the 1/b AND to the 2)
which gives :
b/a=2b
?
Just a question, If I distribute the b on the right, I must also distribute it for 2 ? (Must I distribute to all the right side of the equation ?
1/a=2b ?
c=b+2/a
Yes, I guess I'll still keep practicing. thanks
Okay, Im here. And Bobbym, really haven't you ANY suggestions on how to begin these equations ? I'm feeling that there is no methodology in what Im doing...
AHHHHHHHHHH... okay that why. Mh bobbym, could we continue later this way of doing ? Because I need to go like now. We shall continue later, when I'm online ? Thanks for your help
OKay, but isn't it supposed to be 1+1 on the right side ?...
here is what I did : (like I said, Im not sure how to begin these, to many steps, but the simple ones I can easily do them)
*bu 1/a=1/b+1/u *bu
*a 1/a *bu= 2 *a
bu/2=2a/2
a=bu/2
is the third one a=ub/2 ??? hope i got it
Oh man, I don't know why but I'm having trouble with these. I dont know where to begin and always get a different answer >.< And what I meant by article is something that tells how to approach rearranging formulas
i did the first one
a=s-ut^2
btw, do you have an article on these ? im having a hard time doing these ^^ ty
a(x)a-x/-2=b
b=1/u.a
That would be great, always looking to practice Anyway, I need to go
! BYe
Ok, by curiosity, do you know where I could practice more of these ?
Oh wow.....It's clear now ! I understand now ^^ thanks. The way you present the formula is more clean, I got misleaded by my mess lol