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OK
B
Yes, OK.
I would prefer
Bob
Again we have a rogue 6 in C.
Bob
Yes, that's ok. But you have typed
C = {1, 3, 4, 6}
That 6 cannot be an element as it's not in the universe. Fortunately it doesn't effect your answer.
Bob
A set and its complement divide the 'universe' into two non overlapping sets with no elements left out of being in one or the other. So when you unite them you get everything, ie the universe.
And when you look to find what's in both a set and its complement you find nothing hence the empty set.
Normally when I'm showing union and intersection in a picture I draw two overlapping circles (inside a rectangle for the universe). But for a set and its complement a better picture is a rectangle for the universe divided by a single border making the two sets that don't overlap and together make the whole of the universe rectangle.
Bob
Me too.
Bob
Yes, that's got it!
Bob
The first is correct for set builder notation. Your second answer is the roster answer.
Bob
Yes that's right. I've never heard it called the roster method though. Always good to learn something new.
Bob
I should find A U C first.
A U C = {0, 1, 2, 3, 4, 5} U {2, 4, 6, 8, 10}
A U C = {2, 4}
Yes you should but the union is {0,1,2,3,4,5,6,8,10}
Bob
It is correct.
Bob
Yes, that's correct.
Bob
I only have the same search as you. The keyword can throw up loads of hits. The trick is to remember a word you used that is unlikely to be in anyone else's posts.
I tried 3 people A,B and C and got pages and pages. I think it was finding every post that had any of those in it so then I tried "3 people A,B and C" hoping to find only that specific sentence but still didn't get to it.
Bob
I used the search of users looking for cool* where the * acts as a wildcard. Quite a few hits, but none look like your old account.
Anyone can do this type of search so maybe you can find the exact username yourself. I can then give you access to all your old posts if you wish. There doesn't appear to be a way to link the two accounts however.
Or we can just leave everything as it is.
Bob
hi Turbo
Welcome to the forum and thanks for the puzzles.
Two things I need to check:
y/y isn't that just 1 ?
You've copied these from somewhere. Is there a copyright issue?
Bob
That's excellent , well done!!!
Bob
hi Zach,
Welcome back!
I do remember that question but I cannot find your old username in our lists, nor the thread. Ho hum, not to worry.
Bob
When photons pass through a cloud they are scattered and so arrive in my back garden from a variety of directions. If I knew these directions I could backtrack and, by statistical analysis, determine the most likely direction from which they came.
So it should still be possible to deduce where the shadow would have fallen if only the Sunlight had had an unrestricted path to the dial. Building the supercomputer that can do this analysis in my garden is a project in the early stages of development. As the detectors would have to be sensitive to individual photons, it would also be possible to determine the positions of some of the brighter stars. As the sidereal day is a more reliable time keeping device, not only would it become possible to tell the time at night, but without the annoying correction factor known (incorrectly) as the equation of time.
Bob
Even and Odd are just words for something. So, having thought more about this, they are defined as having the properties ( 2n, and 2n+1) rather than axioms.
A major part of mathematics is concerned with building models to 'describe' something useful. Euclidean geometry, for example, enables us to work with triangles and circles and angles (and lots more) and leads to useful stuff like trigonometry. It's an idealised view because you cannot have a line with zero thickness, nor can you measure an angle with absolute accuracy. Nevertheless, it's very useful.
Number theory is built upon axioms such as x + y = y + x where x and y are real numbers. We can use the axioms to build theorems and then the theorems plus axioms to build new theorems. Eventually you end up with calculus and complex numbers.
The M-W definition looks ok to me.
If you can prove an axiom (presumably from some of the other axioms) then it isn't needed as an axiom, so you could develop your model with one less axiom.
For example. One axiom is "There exists a number (let's call it p for the moment) such that n + p = n. This number is called the additive identity. There is no axiom stating that p is unique because we can prove it.
Proof: suppose there are two identities p1 and p2. Consider the sum p1 + p2. It equals p1 because p2 is an identity, but it also equals p2 because p1 is an identity, thus p1 + p2 = p1 = p2 so the two identities are the same number.
Bob
In "Elementary Real and Complex Analysis" by Shilov, numbers of the form 2n are defined as even, and 2n+1 as odd. These definitions arise early in the axiom list, so you could certainly say they are axioms.
Your proof is therefore enough. I would add a little:
Let n be any integer. Then n + 1 is the next integer, so n and n+1 are consecutive.
Adding them gives n + n + 1 = 2n + 1 which is odd from the definition of an odd number.
Bob
Whose shortest distance from the given line segment is 3cm
It is imprecise. As it stands the locus should include points inside the stadium. That covers the point you're making.
If they only wanted the lines and semicircles it should specify the shortest distance.
Bob
Did you consider the direction of your infinite line? I have received a hyperwave transmission from Alpha Centauri complaining about an infinite line that keeps intersecting their planet (every 24 hours) and, crucially, is interfering with their reception of House* on the interstellar carrier transmitter/receiver. They believe the line originated in your area.
* They are big fans of Hugh Laurie.
It may only be imaginary to you, but, in interstellar carrier transmission/reception, imaginary lines play a significant role. Indeed, without complex numbers it's doubtful such things would be possible
Bob
Using compasses to construct the perpendicular bisector is the correct method. (You could also measure for the midpoint and use a protractor for the perpendicular line but see note below about awarding marks for the construction)
In theory the line extends to infinity in both directions. Clearly, in practice, you have to end the line somewhere. A marker would be looking for your construction so don't erase anything. To show you understand the locus doesn't end where your arcs intersected extend the line beyond those points.
If you really want to be mathematically pedantic you could add a note that your locus extends to infinity.
Bob
Hhmmm. Very primitive. My dial doesn't need batteries and will function for thousands of years. Only snag; the sun has to be shining.
Bob